The equation of variation in which y varies jointly as x and z and inversely as the product of w and p is y=0.5(xz/wp).
Given that variable y varies jointly as x and z and inversely as the product of w and p,where y=7/28 where x=7,z=4,w=7 and p=8.
We are required to find the equation of variation.
To solve this problem we must apply the following procedure:
1) We have that y varies jointly as x and z and inversely as the product of w and p. Therefore we can write the following equation,where k is the constant of proportionality:
y=k(xz/wp)----------1
Now we have to solve for the constant of proportionality as done under:
k=ywp/xz-------------2
Using the values in equation 1.
k=(7/28)(7)(8)/(7)(4)
=0.5
Using all the values in the equation 2.
y=0.5(xz/wp)
Hence the equation of variance is y=0.5(xz/wp).
Question is incomplete.The following values should be included:
y=7/28 where x=7,z=4,w=7 and p=8.
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(0,2)
(8,0)
