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3 years ago

Is triangle DEF congruent to triangle GHI

Mathematics

1 answer:

Studentka2010 [4]3 years ago

8 0

Answer: attatch the image beb

Step-by-step explanation:

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The area of a trapezoid is 1400 cm and the bases measure 20 cm and 50 cm, find the height.

arlik [135]

Using the formulaA=a+b2hSolving forhh=2Aa+b=2·1400 20+50=40cm

4 0

3 years ago

Factor this expression completely, then place the factors in the proper location on the grid. a^3y + 1

ivolga24 [154]

Answer:

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

Step-by-step explanation:

We are to factorize the expression $a^{3y} + 1$ completely. To do this, we will apply the expression below;

The expression can be rewritten as $a^{3y} + 1^{3}$

To factorize the expression, we need to first factorize $(a^{y}+1 )^{3}$ first

$(a^{y}+1 )^{3} =(a^{y}+1 )(a^{y}+1 )^{2}\\= (a^{y}+1 )((a^y)^{2} } + 2a^{y} +1)\\= (a^y)^{3} +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y+1\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +3(a^y)^{2}+3a^y\\$

The we will make $a^{3y} + 1^{3}$ the subject of the formula as shown;

$(a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\(a^y)^{3} + 1^{3} = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$(a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$a^{3y} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

This last result gives the expansion of the expression

7 0

3 years ago

Which ratio is equvalent to 7:3

Gala2k [10]

Answer:

21:18

Step-by-step explanation:

3 0

3 years ago

Help me pls! L need help with this

Sphinxa [80]

Answer:

G. -5/2

Step-by-step explanation:

First we want to distribute the 6 into q and 3.

6q + 18 = 2(q + 4)

Next distribute the 2 into q and 4.

6q + 18 = 2q + 8

Now the variable needs to be on one side of the equation. Subtract 2q from both sides.

4q + 18 = 8

Isolate the variable. Subtract 18 from both sides.

4q = -10

Divide 4 on both sides.

q = -10/4

We can now simplify this even further. Divide -10/4 by 2/2

q = -5/2

4 0

3 years ago

34. The product of two algebraic

S_A_V [24]

Answer:

3a²b

Step-by-step explanation:

The product of two algebraic

terms is 6a3b2. If one of the terms is

2ab, find the other term.

Let us represent

First term = a

Other term = b

a × b = 6a³b²

a = 2ab

b = ?

b = 6a³b²/a

b = 6a³b²/2ab

b = 6a³b²/2a¹b¹

b = (6 ÷ 2) × a^3 - 1 × b ^2 - 1

b = 3a²b

Therefore, the other term = 3a²b

7 0

3 years ago