The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,
where 
and 
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
F(g(3))
f(4 * 3^2 + 9)
f(45)
3 * 45 - 1
134
Prime factorization of 5·2·5=5^2·2
a) Sammie earns
£320×4% = £12.80
each year.
Joel earns
£420×3% = £12.60
each year.
Sammie earns the most interest.
b) Joel's interest after 5 years is
£12.60×5 = £63
so the total amount of money Joel will have is
£420 +63 = £483
Answer:
if you are dividing 299.96 If you are multiplying 26.99
Step-by-step explanation:
If you are dividing: Factor the numerator and denominator and cancel the common factors.
If you are multiplying: Simplify the expression.
