To find the width of a river,a boy places a wooden peg at a point A on one side directly opposite of an object B on the opposite
bank.From A,he walks 50m
along the bank to a point C. He observes that angle ACB =34 degree.Calculate the width of the river.
Guys please help me
2 answers:
27.96m
This resembles a triangle(a right angled triangle in fact!)
If ACB is 34 and AC is 50, we must use trigonometry.
Here we should be using cosine
SOH
CAH
TOA
Cosine = Adjacent/Hypotenuse
Adjacent = BC = x
Hypotenuse = AC = 50
cos(x/50) = 34
Using a calculator,
x = 41.45
Now we should be finding the width of the river ( Line AB)
50² - 41.45² = 781.8975
√781.8975 ≈ 27.96
Thus, width of river is 27.96 cm
Answer:
33.7 m
Step-by-step explanation:
tan ACB = AB/AC
tan 34 = AB/50
AB = 50tan(34)
AB = 33.7254258421
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