(A) 5a +10b -36
(B) 19p + 921
(C) -4a +7b
(D) 7x -9y + 10z
Answer: 12 + 6b
Step-by-step explanation:
Just times both by 6
Given:
The frequency distribution table.
To find:
The mean average score on a test.
Solution:
The frequency distribution table is

x a xa
y b yb
z c zc
Sum a+b+c xa+yb+zc
Now, the mean average score on the test is


Therefore, the mean average score on the test is
.

has CDF

where

is the CDF of

. Since

are iid. with the standard uniform distribution, we have

and so

Differentiate the CDF with respect to

to obtain the PDF:

i.e.

has a Beta distribution

.