Answer:
No
Step-by-step explanation:
An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.
Ahmed is solving
for x.
His steps were:
![\begin{aligned}2\sqrt[3]{x-7}&=-8\\ \sqrt[3]{x-7}&=-4\\ \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\ x-7&=-64 \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D2%5Csqrt%5B3%5D%7Bx-7%7D%26%3D-8%5C%5C%20%20%5Csqrt%5B3%5D%7Bx-7%7D%26%3D-4%5C%5C%20%20%5Cleft%28%5Csqrt%5B3%5D%7Bx-7%7D%5Cright%29%5E3%26%3D%28-4%29%5E3%5C%5C%20%20x-7%26%3D-64%20%5Cend%7Baligned%7D)
Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.
Answer:
12<14
x<12
14>12
14>x
Step-by-step explanation:
I dont know if it is correct but I think it is that way try
The main formula for a polynomial ax^my^n+...
the degree is the sum of the highest degree of the polynomial, it is m+n
<span>the degree of x^3y^2+7x^2y^5-3xy^8 is 9, because </span><span>3xy^8 is the term where we can find a highest value of power (8)
so the degree is degree of x, it is 1 + degree of y (it is 8)
</span>
<h3>
Answer: angle T = angle W</h3>
Explanation:
We are given the sides are congruent due to the tickmarks. Specifically
TU = WV (single tickmarks)
TV = WX (double tickmarks)
So we just need the "A" of "SAS". The A is between the two S letters, so the angle is between the two sides. For triangle TUV, the angle T is between the two sides with the tickmarks. Similarly, angle W is between the tickmarked sides of triangle WVX.
If we know that angle T = angle W, then we have enough information to use SAS.