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Georgia [21]
3 years ago
5

In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find the length of the angle bisector of an

gle ∠A.

Mathematics
1 answer:
nordsb [41]3 years ago
6 0

Check the picture below.

bearing in mind that an angle bisector segment will cut the angle A in two equal halves, thus θ will be half of A.

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What is 0.984÷12.3? If you could show the work that would be awesome​
Stella [2.4K]

Answer:

0.08

Step-by-step explanation:

5 0
3 years ago
What is the first step in solving 2x=y X+y=30
Vanyuwa [196]

Answer: x = 10 y=20

Step-by-step explanation:

You can answer this question by plugging in each equation:

2x=y, x+y=30. Let us plug y as 2x in the second equation x+y=30

x+2x= 30

3x= 30

x=10

After we found x we can then find y by plugging the 10 for x.

2(10) = y

y =20

or you could plug in the other equation

10+y=30

subtract 10 from 30 and we get 20

to double check we can plug in both numbers

2(10) = 20 which is correct

and 10 + 20 = 30 which is correct

8 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
What are the coordinates of the point on the directed line segment from (3,3) to
sergey [27]

Answer:

3,5

Step-by-step explanation:

the answer is 3,5

I hope this helps

5 0
3 years ago
What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5
Anuta_ua [19.1K]

Answer:

y = \frac{3}{2} x-11

Step-by-step explanation:

We are to find the equation a line that passes through the point (8, 1) and which is perpendicular to a line whose equation isy = - \frac{2}{3} x+5.

We know that the slope of line which is perpendicular to another line is the negative reciprocal of the slope of the other line so it will be \frac{3}{2}.

Then, we will find the y-intercept of the line using the standard equation of a line:

y=mx+c

1=\frac{3}{2} (8)+c

c=-11

Therefore, the equation of the line will be y = \frac{3}{2} x-11.


7 0
3 years ago
Read 2 more answers
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