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BlackZzzverrR [31]
2 years ago
10

Which measurement could be a surface area measure? 24 km2 18 m3 63 oz. 12 mm

Mathematics
1 answer:
gulaghasi [49]2 years ago
7 0
24km^2 is your answer because it’s squared
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Given the functions f(x) = 2x -1 and g(x) =
Novosadov [1.4K]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

  • f(x) = 2x - 1
  • g(x) =  2 - x

a)

f(x) + g(x) = (2x - 1) + (2 - x)

                = 2x -1 + 2 - x

                = x + 1

b)

f(x) - g(x) = (2x - 1) - (2 - x)

              = 2x - 1 - 2 + x

               = 3x - 3

c)

g(-5) - f(-5)

Putting x = -5 in g(x) = 2 - x

g(x) = 2 - x

g(-5) = 2 - (-5) = 2+5 = 7

Putting x = -5 in f(x) = 2x - 1

f(x) = 2x - 1

f(-5) = 2(-5) - 1

       = -10 - 1

        = -11

Thus,

g(-5) - f(-5) = 7 - (-11) = 7+11 = 18

d)

f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2

e)

f(g(x)) = f(2-x)

          = 2(2-x)-1

          = 4-2x-1

          = 3-2x

6 0
3 years ago
H(x)=4x+3<br> Domain: all real number<br> Find range
CaHeK987 [17]

don't know if this might help but here

Step-by-step explanation:

(−∞,∞),{y|y∈R}

4 0
2 years ago
1) 0.52 + 1.6 + 8.26 =
Nadya [2.5K]

Step-by-step explanation:

1 10.38

2 16.77

3 11.499

4 11.486

5 0.0947

6 30.52875

7 525

8 32.57862069

9 16.5625

5 0
2 years ago
Why do we use the distributive property when subtracting expressions?
pochemuha

Consider the example

(3x+5) - (x-10)

When we subtract off the (x-10), we are basically subtracting off x and also subtracting off -10. This is the same as adding on 10 because -(-10) = 10

So we would have these steps

(3x+5)-(x-10)

3x+5-x+10

2x+15

Often students forget to distribute the negative all the way through and would have 3x+5-x-10 as an incorrect step. You need to multiply that -1 through to each term, so that's why the distributive property is used.

3 0
3 years ago
Read 2 more answers
B) The price of an electric fan is fixed 20% above its cost price. When it is sold allowing
kenny6666 [7]

Answer:

\boxed{ \boxed{ \sf {Marked \: price \:  = Rs \: 1500}}}

\boxed{ \bold{ \boxed{ \sf{Selling \: price =  \: Rs \: 1230}}}}

Step-by-step explanation:

Let Cost price ( C.P ) be x

<u>Finding </u><u>the </u><u>Marked </u><u>price </u><u>and </u><u>selling </u><u>price </u>

Marked price = \sf{x + 20\% \: of \: x}

⇒\sf{x +  \frac{20}{100}  \times x}

⇒\sf{ \frac{x \times 100 + 20x}{100} }

⇒\sf{ \frac{120x}{100} } ⇒ ( i )

Selling price = \sf{marked \: price \:  - 18\% \: of \: marked \: price}

⇒\sf{ \frac{120x}{100} -  \frac{18}{100}  \times  \frac{120x}{100} }

⇒\sf{ \frac{120x}{100}  -  \frac{54x}{250} }

⇒\sf{ \frac{120x \times 5 - 54x \times 2}{500} }

⇒\sf{ \frac{600x - 108x}{500} }

⇒\sf{ \frac{492x}{500} } ⇒ ( ii )

<u>Finding </u><u>the </u><u>value </u><u>of </u><u>x </u><u>(</u><u> </u><u>Cost </u><u>price </u><u>)</u>

\sf{loss = cost \: price - selling \: price}

⇒\sf{20 = x -  \frac{492x}{500} }

⇒\sf{20  =  \frac{x \times 500 - 492x}{500} }

⇒\sf{20 =  \frac{8x}{500} }

⇒\sf{8x = 10000}

⇒\sf{x =  \frac{10000}{8} }

⇒\sf{x = \: Rs \:  1250}

Value of x ( cost price ) = Rs 1250

<u>Now</u><u>,</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>i </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>marked </u><u>price</u>

\sf{marked \: price =  \frac{120x}{100} }

⇒\sf{ \frac{120 \times 1250}{100} }

⇒\sf{   \: Rs \: 1500}

<u>Replacing </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>ii </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>selling </u><u>price</u>

\sf{selling \: price =  \frac{492 \: x}{500} }

⇒\sf{ \frac{615000}{500} }

⇒\sf{ \: Rs \: 1230}

Thus , Marked price of the fan = Rs 1500

Selling price of the fan = Rs 1230

Hope I helped!

Best regards!!

6 0
3 years ago
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