They attract each other with force
F=q1*q2/(4πεr^2), where
q1=2.4 µC, q2=4.2 µC,
r=4.9·10-2 m, ε=8.854·10^(-12) SI units.
♦ F=2.4·10-6 * 4.2·10-6 /(4*pi* 8.854·10^(-12) *0.049^2)=
=37.73 N;
It was <em>(1/2) (Net force on the cart) m/s²) </em>.
Ray B. isn't possible for a converging lens, because after passing through focus ot would go parallel to the principal axis,
So, Correct option is :
=》Option B.)
Answer:
Work done = 838470 Joules.
Explanation:
Given the following data;
Power = 19 hp
Time = 1 minute to seconds = 60 seconds.
Next, we would convert the unit of power in "hp" to "Watt."
1 Watt = 0.00135962 horsepower
x Watt = 19 horsepower
Cross-multiplying, we have;
19 = 0.00135962x
x = 19/0.00135962
x = 13974.5 Watts.
Now, to find the work done in moving the mower;
Work done = power * time
Substituting into the formula, we have;
Work done = 13974.5 * 60
Work done = 838470 Joules.
A chemical process with an e-factor of 1 creates less waste than an e-factor of 25 is True.
<h3>What do you mean by E-factor?</h3>
The actual amount of waste produced during the process—which is referred to as anything other than the targeted product—is known as the E factor. It considers the chemical yield as well as reagents, solvent losses, all process aids, and, in theory, fuel (although this is often difficult to quantify). There is one exception: I often did not include water in the E factor calculation. For instance, only the inorganic salts and organic chemicals present in an aqueous waste stream are taken into account; the water itself is left out. In many instances, the inclusion of water used in the process might result in very high E factors, which can make it challenging to compare processes in a meaningful way.
To learn more about E-factor, Visit:
brainly.com/question/12183753
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