Answer:
Explanation:
distance travelled s = 10 cm
speed v = 1.4 x 10⁶ m /s
v² = u² + 2as
u = 0
v² = 2as
( 1.4 x 10⁶ )² = 2 x a x .10
a = 9.8 x 10¹² m /s²
force on proton = mass x acceleration
= 1.67 x 10⁻²⁷ x 9.8 x 10¹²
= 16.366 x 10⁻¹⁵ N .
If magnitude of electric field be E
force on proton
= E x charge on proton
= E x 1.6 x 10⁻¹⁹
E x 1.6 x 10⁻¹⁹ = 16.366 x 10⁻¹⁵
E = 10.22 x 10⁴ N/C
The direction of electric field will be positive x - direction .
b )
Speed of proton = 1.4 x 10⁶ m /s .
Answer:
ΔL = 0.429 m
Explanation:
The expression for linear thermal expansion is
ΔL = α L₀ ΔT
the coefficient of linear expansion of steel is 11 10⁻⁶ ºC⁻¹
the initial length of the bridge is L₀ = 1.30 10³ m and the temperature variation is ΔT = 30 ºC
calculate
ΔL = 11 10⁻⁶ 1.30 10³ 30
ΔL = 4.29 10⁻¹ m
ΔL = 0.429 m
Because the core is the hottest place at which it holds the most heat to bring it out to be towards africa.
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Answer:
the maximum height of Joe's ball will be 4 times Bill's ball.
Explanation:
let bill's velocity be v then Joe's velocity is 2v.
and initial velocities of both bill and Joe are 0
for Bill


for Joe


thus we can write that
h'=4h
the maximum height of Joe's ball will be 4 times Bill's ball.
Answer:
the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s
Explanation:
The computation of the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is as follows:
The ball momentum is

As there is a similar momentum
So,

Hence, the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s