Answer:
a.2.5x 10^3 m/s
b.mr=48kg/s
Explanation:
A rocket is moving away from the solar system at a speed of 7.5 ✕ 103 m/s. It fires its engine, which ejects exhaust with a speed of 5.0 ✕ 103 m/s relative to the rocket. The mass of the rocket at this time is 6.0 ✕ 104 kg, and its acceleration is 4.0 m/s2. What is the velocity of the exhaust relative to the solar system? (B) At what rate was the exhaust ejected during the firing?
velocity of the exhaust relative to the solar system
velocity of the rocket -velocity of the exhaust relative to the rocket.
7.5 ✕ 103 m/s-5.0 ✕ 103 m/s
2.5x 10^3 m/s
. b we will look for the thrust of the rocket
T=ma
T=6.0 ✕ 104 kg*4.0 m/s2
T=2.4*10^5N
f=mass rate *velocity of the exhaust
T=2.4*10^5N=mr*5.0 ✕ 10^3 m/s
mr=2.4*10^5N/5.0 ✕ 10^3
mr=48kg/s
If you increase speed you have to increase force to keep a balance Newton's second law.
Answer:
<em>300 W</em>
<em></em>
Explanation:
power of each bulb P = 75 W
voltage in the circuit = 120 V
we know that electrical power P = IV ....1
and V = IR
we can also say that I = V/R
substituting for I in equation 1, we have
P =
....2
The total total power in the circuit = 75 x 2 = 150 W
from equation 2, we have
150 = 
R =
= 96 Ω this is the resistance of the whole circuit.
This resistance is due to the two light bulbs, for each light bulb since they are arranged in series
R = 96/2 = 48 Ω
From P =
for each light bulb, power is
P =
= <em>300 W</em>
<h2>
FAULT</h2>
The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts. The fault labeled 'E' cuts through all three sedimentary rock layers (A, B, and C) and also cuts through the intrusion (D). So the fault must be the youngest formation that is seen.
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
Average speed=total distance travelled/time