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wlad13 [49]
2 years ago
10

A ray of light crosses a boundary between two transparent materials. The medium the ray enters has a larger index of refraction.

Which of the following statements are true?
a) The wavelength of the light increases as it transitions between materials
b) The speed of the light remains constant as it transitions between materials.
c) The frequency of the light remains constant as it transitions between materials.
d) The wavelength of the light decreases as it enters into the medium with the greater index of refraction.
e) The wavelength of the light remains constant as it transitions between materials.
f) The speed of the light decreases as it enters into the medium with the greater index of refraction.
g) The frequency of the light decreases as it enters into the medium with the greater index of refraction.
h) The frequency of the light increases as it enters into the medium with the greater index of refraction.
i) The speed of the light increases as it enters the medium with the greater index of refraction.
Physics
1 answer:
Liula [17]2 years ago
7 0

The wavelength of the light decreases as it enters into the medium with the greater index of refraction. The wavelength of the light remains constant as it transitions between materials.

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A man standing 1.54 m in front of a shaving mirror produces a real, inverted image 15.2 cm from it. What is the focal length of
zavuch27 [327]

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The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

Explanation:

Given that,

Object distance u=1.54 m =154 cm

Image distance v = 15.2 cm

Magnification = 2

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{15.2}+\dfrac{1}{-154}

\dfrac{1}{f}=\dfrac{347}{5852}

f=16.86\ cm

We need to calculate the focal length

Using formula of magnification

m= \dfrac{-v}{u}

Put the value into the formula

2=\dfrac{v}{u}

v = -2u

Using formula of for focal length

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{16.86}=\dfrac{1}{u}-\dfrac{1}{2u}

\dfrac{1}{16.86}=\dfrac{1}{2u}

2u=16.86

u=\dfrac{16.86}{2}

u=8.43\ cm

Hence, The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

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