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Ymorist [56]
3 years ago
11

Solve for w.

Mathematics
1 answer:
kherson [118]3 years ago
7 0

Answer:

w = 2 or w = -2

Step-by-step explanation:

-9|w| = -18

divide by -9 on both sides

w = 2 negative 2 works also

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Question 15 A party rental company has chairs and tables for rent. The total cost to rent 8 chairs and 3 tables is $38 . The tot
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2 years ago
There are 100 people in a wedding house, including children, men and women, and there are 100 pappadas to give with Sadya Te.
olga nikolaevna [1]

Answer:

Two possible sets of answers.

5 men, 11 women and 42 children, or

10 men, 2 women and 88 children

Selamat Sadhya!

Step-by-step explanation:

M = number of men

W = number of women

100-M-W = number of children

Total number of pappadas

5M+3W+(100-M-W)/2 = 100

Solve for W

W = (100-9M)/5 .......................(1)

Examine equation (1).

In order to have W as a whole number, M must be multiple of 5

Therefore M = 5 or 10

If M = 5, W = (100-45)/5 = 11 and children = 100-5-11 =  84

If M = 10, W = (100-90)/5 = 2 and children = 100-10-2 = 88

8 0
3 years ago
What are the two major theories of how Native American arrived in the Western Hemisphere? Which is the most popular and also exp
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The land bridge (Bering strait) and the crossing from Canada
4 0
2 years ago
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad 
C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}
\\\\\\
AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad 
D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}
\\\\\\
BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}
\\\\\\
BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]
\\\\\\
4[15]\implies 60

7 0
2 years ago
Read 2 more answers
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