Answer:
The object will hit the ground after 10.308 seconds.
Step-by-step explanation:
h(t) = -16t² + 1700
If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.
-16t² + 1700 = 0 Plug this into a calculator if you have one.
t = -10.308 and t = 10.308
Since time can't be negative, your answer will be the positive value, 10.308.
Answer:
It has a maximum
Step-by-step explanation:
The way I think about it is looking at "a" (the leading variable's coefficient, so __x²), if it's negative, the graph is a frown, but if it's positive, it's a smile. In this case, a is -2, so the graph would have the shape of a frown, which has a maximum.
I hope this helped!
Can’t help you with this, we need either the picture of the graph or the formula for the graph
Answer:
x = 60
1) 60
2) 360
3) 160
60 + 360 + 160 = 580
Step-by-step explanation:
1) x
2) 6x
3) x + 100
x + 6x + x + 100 = 580
8x = 580 - 100
x = 480/8
x = 60
