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svp [43]
3 years ago
12

You are working on an assignment for your statistics class. You need to estimate the proportion of students at your college who

delay taking their first math class for at least one year. Which sampling plan will produce the most reliable results?
A, Obtain a list of all students enrolled at the college. Randomly select 100 students from the list.
B, Work with the math instructors to create a list of students currently taking a math class. Randomly select 200 students from the list.
C, Visit the cafeteria on multiple days at different times. Randomly select students who are using the cafeteria until 300 are selected.
D, Randomly select ten math classes. Survey every student in each of the ten classes. (Sample size will be abou
Mathematics
1 answer:
Ede4ka [16]3 years ago
6 0

Answer:

B, Work with the math instructors to create a list of students currently taking a math class. Randomly select

Step-by-step explanation:

Let's think of each scenario at a time.

(A) We select 100 students enrolled in college randomly that should be fine because we are taking only students that can take classes. this rules out faculty members and any other persons but also there may be students that will never take any math course as part of their study plan, this is ruled out on that basis.

(B)if we take 100 students from the list of math instructor, that will ensure that we have taken students that are taking math class now, and math is part of their study plan, seems fine.

(C) visiting cafeteria randomly on multiple days will give us random persons that may not even be enrolled in university. this can be ruled out on that basis.

(D)Ten class at random and surveying each student in every class will make sampling size large or small depending on students enrolled in each of the class this will not give us reliable results.

We can conclude that (B) is the beast method for obtaining reliable results.

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Answer:

The point estimate for \mu is 8.5 hours.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem

We are working with a sample of 81 adults, so the point estimae of the mean  is the mean number of weekly hours that U.S. adults use computers at home.

So, the point estimate for \mu is 8.5 hours.

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JulsSmile [24]

Answer:

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Step-by-step explanation:

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mafiozo [28]

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Step-by-step explanation:

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Hope this helps!

May I have brainliest? :D

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