Question

Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r'), what is C' if d d' = 0.25 and C = 6?

Answer 1

Answer:

$C'=24\ units$

Step-by-step explanation:

we know that

Since all circles are similar to each other

The ratio of the circumferences of two circles is equal to the scale factor

The ratio of the diameters of two circles is equal to the scale factor

so

The ratio of the circumferences of two circles is equal to the ratio of its diameter

therefore

$\frac{C}{C'}=\frac{d}{d'}$

we have

$\frac{d}{d'}=0.25$

$C=6\ units$

substitute

$\frac{6}{C'}=0.25$

$C'=\frac{6}{0.25}=24\ units$