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Aleksandr [31]
3 years ago
6

HELP PLEASE ASAP!!!!! Alex can cut a cord into 7 pieces in 36 seconds. How long will it take him to cut the cord into 12 pieces?

Mathematics
1 answer:
lbvjy [14]3 years ago
5 0

Answer:

GIVE ME BRAINLIEST

Step-by-step explanation:

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The slope of diagonal PQ is _____ , and its equation is _______
Gelneren [198K]
<span>The slope of diagonal PQ is zero, and its equation is y = 2. Slope is defined as the rise over the run. Since there is no rise, that is, the rise is zero, then zero over a number is zero.</span>
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Solve the inequality 24&lt;5x-1
Katena32 [7]

Answer:

5 < x

Step-by-step explanation:

24<5x-1

Add 1 to each side

24+1<5x-1+1

25 < 5x

Divide by 5

25/5 < 5x/5

5 < x

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3 years ago
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Let f be a continuous function defined on the interval [0,1] such that f(0) = f(1). Show that there exists a number 0 &lt;= a &l
Leni [432]

Explanation:

In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula g(x) = f(x+1/2)-f(x) .

If we evaluate g at the  endpoints we have

g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))  

g(1/2) = f(1) - f(1/2) = -g(0)

Since g(1/2) = -g(0), we have one chance out of three

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  • g(0) < 0 and g(1/2) > 0
  • g(0) = g(1/2) = 0

We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0.  This proves that g has at least one zero on [0,1/2].

Let c be a 0 of g, then we have

0 = g(c) = f(c+1/2)-f(c)

Hence, f(c+1/2) = f(c) as we wanted.

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3 years ago
How do i factorize x²-6x-16?​
topjm [15]

Step-by-step explanation:

need a thanks and thats it...

8 0
3 years ago
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How many different menus showing 10 main courses can a restaurant make if it has 15 main courses from which to choose? 360,360 3
PtichkaEL [24]

Answer:

3003

Step-by-step explanation:

The number of differents menus containing 10 main courses that the restaurant can make if it has 15 main courses from which to chose is calculated through the combination: 15C10. The formula of the combination is: nCr = n! / ((r!) x(n - r)!) 

Where r=10 and n=15

Substituting the values to the equation: 15C10 = 15! / (10!)x(10 - 5)! = 3003

Then there are 3003 different menus that a restaurant can makeif it has 15 main courses from which to choose.

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