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3 years ago

The basketball players at

Mathematics

2 answers:

kupik [55]3 years ago

8 0

Give us more information

bazaltina [42]3 years ago

8 0

Answer:

The basketball players at the game, are very talented. There is a sentenceif thats what you wanted.

Step-by-step explanation:

You might be interested in

What is bigger 20g or 0.02kg

WITCHER [35]

20g is .02kg. They are the same size.
Hope this helps!

5 0

3 years ago

5x+4(-x-2) = -5x + 2(x-1)+12 solve for x

vivado [14]

Hello!

Answer:

$\huge\boxed{x = 4.5}$

Starting with:

5x + 4(-x - 2) = -5x + 2(x - 1) + 12

Distribute terms outside of the parenthesis:

5x + 4(-x) + 4(-2) = -5x + 2(x) + 2(-1) + 12

5x - 4x - 8 = -5x + 2x - 2 + 12

Combine like terms:

x - 8 = -3x + 10

Isolate for the "x" variable by adding 3x for both sides:

4x - 8 = 10

Add 8 to both sides:

4x = 18

Divide both sides by 4:

x = 18/4

x = 4.5

Hope this helped! :)

3 0

3 years ago

Read 2 more answers

While catching fireflies, you and a friend decide to have a competition. After m minutes, you have (3m+13) fireflies and your fr

scoundrel [369]

Answer:

7m + 19 should be the answer

Step-by-step explanation:

total 7m + 19

3 0

3 years ago

If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),

belka [17]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0

3 years ago

Read 2 more answers

Q2. On a cold day, hailstones fall with a velocity of (2i− 6k) m s−1 . If a cyclist travels through the hail at 10i ms−1 , what

Kobotan [32]

Answer: $-8\hat{i}-6\hat{k}$

$\theta =\tan^{-1}\left ( \frac{3}{4} \right )$

Step-by-step explanation:

Given

Velocity of hailstones fall $\left ( V_h\right )=2\hat{i}-6\hat{k}$ m/s

Velocity of cyclist $\left ( V_c\right )=10\hat{i}$ m/s

Therefore

Velocity of hail with respect to cyclist $\left ( V_{hc}\right )$

$V_{hc}=V_h-V_c$

$V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}$

$V_{hc}=-8\hat{i}-6\hat{k}$

and angle of hails falling relative to the cyclist is given by

$\theta =\tan^{-1}\left ( \frac{3}{4}\right )$

$\theta$ is the angle made with the vertical

5 0

3 years ago