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KIM [24]
3 years ago
5

The length of Rebecca’s rectangular garden was two times the width “w”. She increased the length and width of the garden so that

the area of the new garden is (2w2+7w+6)square yards. By how much did Rebecca increase the length and width of the garden. Show your complete working.
Mathematics
1 answer:
Damm [24]3 years ago
6 0

Answer:

rebecca increased the length by 3 and the width by 2

Step-by-step explanation:

First we need to find the length and width by factorizing the expressio ofr the area;

A = 2w^2+7w+6

A = 2w^2+4w+3w+6

A = 2w(w+2)+3(w+2)

A = (2w+3)(w+2)

Since l = 2w

Length = 2w+3

width = w+2

This shows that rebecca increased the length by 3 and the width by 2

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Select the correct answer.
Nuetrik [128]

Answer:

1652w-1652  is equivalent to \left(2w-2\right)\left(826\right)

In other words:

\left(2w-2\right)\left(826\right)=\:1652w-1652

Step-by-step explanation:

Considering the expression

\left(2w-2\right)\left(826\right)

solving

\left(2w-2\right)\left(826\right)

=\left(826\right)\left(2w-2\right)

\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac

a=\left(826\right),\:b=2w,\:c=2

=\left(826\right)\cdot \:2w-\left(826\right)\cdot \:2

=826\cdot \:2w-826\cdot \:2

=1652w-1652

Therefore,

1652w-1652  is equivalent to \left(2w-2\right)\left(826\right)

In other words:

\left(2w-2\right)\left(826\right)=\:1652w-1652

5 0
3 years ago
Nine more than the quotient of a number k and negative eleven
Bumek [7]

(k/-11)+9

or (-1 / 11)k + 9

3 0
3 years ago
in Seattle it rained 265 days last year and239 days the year before. About how many more days did it rain last year then the yea
Maksim231197 [3]

Answer:36


Step-by-step explanation:

265-239

minus 5 and nie make five 15 and minus from nine that equals 6

6-3=3

200-200=0

so the answer is 36



8 0
3 years ago
Pete's Pasteris sells cupcakes in packs of 4. A caterer needs between 42 and 50 cupcakes for dessert. Name two possible number b
anyanavicka [17]

Answer:

44 48

Step-by-step explanation:

8 0
2 years ago
Law of sines: How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3?
butalik [34]
According to the law of sines:

\frac{a}{sin(A)} = \frac{b}{sin(B)}

Using the given values, we can find the angle B and find the number of possible triangles that can be formed.

\frac{2}{sin(75)}= \frac{3}{sin(B)} \\  \\ 
sin(B)=3* \frac{sin75}{2}  \\  \\ 
sin(B)=1.45 \\  \\ 
B=sin^{-1} (1.45)

The range of sin is from -1 to 1. The above expression does not yield any possible value of B, as sin of no angle can be equal to 1.45.

Therefore, we can conclude that no triangle exists with the given conditions.
5 0
3 years ago
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