The answer to the problem is -5
<span>Susanne is 16 years old.</span>
b = Bob's age
s = Susanne's age
d = Dakota's age
Bob's age is 4 times greater than Susanne's age:
b = 4s
Dakota is three years younger than Susanne:
d = s - 3
The sum of Bob's, Susanne's, and Dakota's ages is 93:
b + s + d = 93
solve these equations:
b = 4s
d = s - 3
b + s + d = 93
and get:
b = 64 years
s = 16 years
(remember that s = Susanne)
d = 13 years
Answer:
x=3/8, y=-7/8. (3/8, -7/8).
Step-by-step explanation:
y=-5x+1
y=3x-2
----------
-5x+1=3x-2
-5x-3x+1=-2
-8x+1=-2
-8x=-2-1
-8x=-3
8x=3
x=3/8
y=3(3/8)-2=9/8-2=9/8-16/8=-7/8
