Answer:
Charles Babbage invented computer.
hope this helps!
Answer:
Advantages: computers don't make human error
It can be used for communication
Ease of access
Disadvantages: computers can be a distraction
Potential loss of privacy
It can limit learning and create a dependency
Answer:
B but don't be surprised if it is not the answer given. It's just the best of a bunch of poor choices.
Explanation:
This is actually not an easy question to answer. It's one of those answers that has elements of "Some do and Some don't" in them.
A: is not true for painters and it is not necessarily true for C for painters.
D: photographer can pose his subjects. A painter can pose someone, but not always.
C: Answered under A.
I think the answer you are forced to choose is B, but neither one has to do it. Still life painters ( a bowl of fruit, a bouquet of flowers) and photographs pose the subjects carefully and do not want the fruit or flowers to move around.
I'd pick B, but it does not have to be the answer. I just think it is less wrong than the others.
Answer:
B.
Slides or positive films give high quality pictures with higher color saturation and contrast.
Explanation:
The above is true for slides with positive film. This is because, the positive film happens to have a high resolution when it was been used thereby giving out a high quality video at the end of the recording. The higher colour saturation and contrast are also an attribute of a slide or positive film.
Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
