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Yuliya22 [10]
4 years ago
10

Lea left home and drove toward the ferry office at an average speed of 22 km.H. Trevon left at the same time and drove in the op

posite direction with an average speed of 43 km/h. How long does Trevon need to drive before they are 65 km apart?
Mathematics
1 answer:
Alik [6]4 years ago
4 0

Answer:

1 hour

Step-by-step explanation:

Lea's speed = 22km/hr

Trevon's speed = 43km/hr in a direction opposite Lea's

How long does Trevon needs to drive before they are 65km apart.

Note : both took at the same time and in opposite direction.

Recall : speed = distance / time

Distance = speed * time

Distance between them = 65km

Let Trevon's distance = D2 = 43 * t

Lea's distance = D1 = 22 * t

t is the same since they both left at the same time.

D2 + D1 = 65

43t + 22t = 65

65t = 65

t = 65/65

t = 1 hour

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Step-by-step explanation:

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simplify

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What is the least number of colors you need to correct color in the sections of these pictures so that no two touching sections
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You would assume that in this figure, the number of colored sections with which are not colored with respect to a " touching " colored section, would be half of the total colored sections. However that is not the case, the sections are not alternating as they still meet at a common point. After all, it notes no two touching sections, not adjacent sections. Their is no equation to calculate this requirement with respect to the total number of sections.

Let's say that we take one triangle as the starting. This triangle will be the start of a chain of other triangles that have no two touching sections, specifically 7 triangles. If a square were to be this starting shape, there are 5 shapes that have no touching sections, 3 being a square, the other two triangles. This is presumably a lower value as a square occupies two times as much space, but it also depends on the positioning. Therefore, the least number of colored sections you can color in the sections meeting the given requirement, is 5 sections for this first figure.

Respectively the solution for this second figure is 5 sections as well.

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Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume (V), in cubic centimeters, and surface area (A_{s}), in square centimeters, of the box with a square base are described below:

A_{s} = l^{2}+h\cdot l (1)

V = l^{2}\cdot h (2)

Where:

l - Side length of the base, in centimeters.

h - Height of the box, in centimeters.

By (2), we clear h within the formula:

h = \frac{V}{l^{2}}

And we apply in (1) and simplify the resulting expression:

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A_{s}\cdot l = l^{3}+V

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Then, we find the first and second derivatives of this expression:

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Then, we evaluate this result in the expression of the second derivative:

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The largest possible volume of the box is 2000000 cubic meters.

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3 years ago
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