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Yuliya22 [10]
3 years ago
10

Lea left home and drove toward the ferry office at an average speed of 22 km.H. Trevon left at the same time and drove in the op

posite direction with an average speed of 43 km/h. How long does Trevon need to drive before they are 65 km apart?
Mathematics
1 answer:
Alik [6]3 years ago
4 0

Answer:

1 hour

Step-by-step explanation:

Lea's speed = 22km/hr

Trevon's speed = 43km/hr in a direction opposite Lea's

How long does Trevon needs to drive before they are 65km apart.

Note : both took at the same time and in opposite direction.

Recall : speed = distance / time

Distance = speed * time

Distance between them = 65km

Let Trevon's distance = D2 = 43 * t

Lea's distance = D1 = 22 * t

t is the same since they both left at the same time.

D2 + D1 = 65

43t + 22t = 65

65t = 65

t = 65/65

t = 1 hour

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