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ankoles [38]
3 years ago
14

What is the sign of the product? Help plz

Mathematics
1 answer:
klio [65]3 years ago
6 0
A positive
as there are 4 negetive multiplied
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Pls help urgent
tangare [24]
It's just asking for the gradient basically
150/3 = 50
Or technically -50 because it's decreasing
7 0
3 years ago
Plz help me do em all ill mark u brainliest and give u 5 stars
zlopas [31]
Answer for #9 : 24,720
Answer for #10 : 145
6 0
3 years ago
Can someone help me thank youuu!!!
andrew-mc [135]

Answer:

D.

Step-by-step explanation:

cos is positive and sin is negative

=>

it must be in quadrant IV.

you remember, 1 = sin² + cos²

1 = sin² + (3/5)² = sin² + 9/25

25/25 = sin² + 9/25

16/25 = sin²

sin = 4/5 or -4/5

and as sin of this angle is < 0, our solution is -4/5

4 0
3 years ago
An=an-1+6an-2 <br> n&gt;2 a0=3 a1=6
Svetach [21]
\begin{cases}a_0=3\\a_1=6\\a_n=a_{n-1}+6a_{n-2}&\text{for }n>2\end{cases}

Let the generating function for a_n be

A(x)=\displaystyle\sum_{n\ge0}a_nx^n

Multiplying both sides by x^{n-2}

a_nx^{n-2}=a_{n-1}x^{n-2}+6a_{n-2}x^{n-2}

Summing both sides over the non-negative integers greater than or equal to 2 gives

\displaystyle\sum_{n\ge2}a_nx^{n-2}=\sum_{n\ge2}a_{n-1}x^{n-2}+6\sum_{n\ge2}a_{n-2}x^{n-2}
\displaystyle\frac1{x^2}\sum_{n\ge2}a_nx^n=\frac1x\sum_{n\ge1}a_nx^n+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(\sum_{n\ge0}a_nx^n-a_0-a_1x\right)=\frac1x\left(\sum_{n\ge0}a_nx^n-a_0\right)+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(A(x)-3-6x\right)=\frac1x\left(A(x)-3\right)+6A(x)
A(x)=\dfrac{3x+3}{1-x-6x^2}
A(x)=\dfrac3{5(1+2x)}+\dfrac{12}{5(1-3x)}

For |x|, the two series converge to

\displaystyle A(x)=\frac35\sum_{n\ge0}(-2x)^n+\frac{12}5\sum_{n\ge0}(3x)^n
\implies A(x)=\displaystyle\sum_{n\ge0}\dfrac{3(-2)^n+12(3)^n}5x^n
a_n=\dfrac{3(-2)^n+12(3)^n}5=\dfrac{3(-2)^n+4(3)^{n+1}}5
5 0
3 years ago
I NEED HELP ASAP!!! Two angles are supplementary. The measure of one angle is 6 less than 20% of the other. find both angles.
Mamont248 [21]

Answer:

Step-by-step explanation:

3 0
3 years ago
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