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3 years ago

What is the sign of the product? Help plz

Mathematics

1 answer:

klio [65]3 years ago

6 0

A positive
as there are 4 negetive multiplied

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Pls help urgent

tangare [24]

It's just asking for the gradient basically
150/3 = 50
Or technically -50 because it's decreasing

7 0

3 years ago

Plz help me do em all ill mark u brainliest and give u 5 stars

zlopas [31]

Answer for #9 : 24,720
Answer for #10 : 145

6 0

3 years ago

Can someone help me thank youuu!!!

andrew-mc [135]

Answer:

Step-by-step explanation:

cos is positive and sin is negative

it must be in quadrant IV.

you remember, 1 = sin² + cos²

1 = sin² + (3/5)² = sin² + 9/25

25/25 = sin² + 9/25

16/25 = sin²

sin = 4/5 or -4/5

and as sin of this angle is < 0, our solution is -4/5

4 0

3 years ago

An=an-1+6an-2 <br> n>2 a0=3 a1=6

Svetach [21]

$\begin{cases}a_0=3\\a_1=6\\a_n=a_{n-1}+6a_{n-2}&\text{for }n>2\end{cases}$

Let the generating function for $a_n$ be

$A(x)=\displaystyle\sum_{n\ge0}a_nx^n$

Multiplying both sides by $x^{n-2}$

$a_nx^{n-2}=a_{n-1}x^{n-2}+6a_{n-2}x^{n-2}$

Summing both sides over the non-negative integers greater than or equal to 2 gives

$\displaystyle\sum_{n\ge2}a_nx^{n-2}=\sum_{n\ge2}a_{n-1}x^{n-2}+6\sum_{n\ge2}a_{n-2}x^{n-2}$
$\displaystyle\frac1{x^2}\sum_{n\ge2}a_nx^n=\frac1x\sum_{n\ge1}a_nx^n+6\sum_{n\ge0}a_nx^n$
$\displaystyle\frac1{x^2}\left(\sum_{n\ge0}a_nx^n-a_0-a_1x\right)=\frac1x\left(\sum_{n\ge0}a_nx^n-a_0\right)+6\sum_{n\ge0}a_nx^n$
$\displaystyle\frac1{x^2}\left(A(x)-3-6x\right)=\frac1x\left(A(x)-3\right)+6A(x)$
$A(x)=\dfrac{3x+3}{1-x-6x^2}$
$A(x)=\dfrac3{5(1+2x)}+\dfrac{12}{5(1-3x)}$

For $|x|$ , the two series converge to

$\displaystyle A(x)=\frac35\sum_{n\ge0}(-2x)^n+\frac{12}5\sum_{n\ge0}(3x)^n$
$\implies A(x)=\displaystyle\sum_{n\ge0}\dfrac{3(-2)^n+12(3)^n}5x^n$
$a_n=\dfrac{3(-2)^n+12(3)^n}5=\dfrac{3(-2)^n+4(3)^{n+1}}5$

5 0

3 years ago

I NEED HELP ASAP!!! Two angles are supplementary. The measure of one angle is 6 less than 20% of the other. find both angles.

Mamont248 [21]

Answer:

Step-by-step explanation:

3 0

3 years ago