Area = 38 1/4 = 153/4

Width = 4 1/2 = 9/2

Area = Length x Width

Length = Area/Width

So divide both of them:
$\sf{ \frac{153}{4} \div \frac{9}{2} =\sf{ \frac{153}{4} \times \frac{2}{9} = \frac{9 \times 17}{2\times 2}\times \frac{2}{9} = \frac{17}{2}$

So the length is equal to $\boxed{\sf{\frac{17}{2}}}$

4 0

3 years ago

8) A pyramid has a rectangluar base with length 12 km and width of 5 km. If the volume is 200

SashulF [63]

Hi there!

$\large\boxed{h = 10km}$

We know that the equation for the volume of a pyramid is:

V = 1/3(bh)

We know that:

V = 200 km³

b = 12 × 5 = 60 km²

We can plug these into the equation:

200 = 1/3(60)(h)

Simplify:

200 = 20h

Divide both sides by 20:

200/20 = 20h/20

h = 10 km

6 0

3 years ago

Help me with this question

kaheart [24]

First combine like terms and put the expression in standard form. This expression is now in simplest form and cannot be simplified anymore.
3a + 10ab - 7a^2b - 10ab^2 + 12ab - (-4) + (-a^2b) - 5a
-10ab^2 - 8a^2b -2a + 24ab - (-4)

Hope this helps

5 0

3 years ago