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andreev551 [17]
3 years ago
11

there were 96 runners to start a race. in the first half of the race, 1/4 of them dropped out. in the second half of the race, 1

/6 of the remaining runners dropped out. how many runners finished the race?
Mathematics
1 answer:
AlekseyPX3 years ago
4 0

Answer: 60

Step-by-step explanation: 1/4 of 96 is 24 so you subtract that and get 72. And 1/6 of 72 is 12 and you subtract that leaving you with 60 to remain.

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Alex17521 [72]
I do need help please
6 0
3 years ago
Find the GCF of the following literal terms.<br><br> m^7 n^4 p^3 and mn^12 p^5
Dvinal [7]
m^7n^4p^3=mn^4p^3\cdot m^6\\\\mn^{12}p^5=mn^4p^3\cdot n^8p^2\\\\GCF(m^7n^4p^3;\ mn^{12}p^5)=mn^4p^3
6 0
2 years ago
Which graph represents the solution to this inequality? 16x - 80x &lt; 37 + 27
AlladinOne [14]

Answer: ​107

Step-by-step explanation:

1 Remove parentheses.

16x-80<2716x−80<27

2 Add 8080 to both sides.

16x<27+8016x<27+80

3 Simplify  27+8027+80  to  107107.

16x<10716x<107

4 Divide both sides by 1616.

x<\frac{107}{16}x<

​16

​

​107

​​  

Done

3 0
3 years ago
Which of the equations below represents a line perpendicular to the x-axis?
Allushta [10]

Answer:

Option B

Step-by-step explanation:

we know that

A line perpendicular to the x-axis is a line parallel to the y-axis

so

the equation of the line is of the form x=(+/-)a

The slope of the line is undefined

where

a is a real number

therefore

x=6 is a line perpendicular to the x-axis

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by
Fudgin [204]

The given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

Given that, the expression can be written as.

(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)

By simplifying the above equation,

\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}

By taking out the common terms from the equation,

\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}

By simplifying the above equation by cancel out the common factors.

\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}

Now, by taking (-1) common from (-2c+1) we get,

\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}

By simplifying the above equation, we get the expression,

-3c

So the given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

7 0
2 years ago
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