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olga55 [171]
3 years ago
13

HELP PLEASE!!!!

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

The answer is D.. 2^0

Step-by-step explanation:

i had the same question in my program

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Question #12 Please help
julia-pushkina [17]
\bf \textit{logarithm of factors}\\\\
log_a(xy)\implies log_a(x)+log_a(y)
\\\\\\
\textit{Logarithm of rationals}\\\\
log_a\left(  \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\\\
\textit{Logarithm of exponentials}\\\\
log_a\left( x^  b \right)\implies   b\cdot  log_a(x)\\\\
-------------------------------\\\\


\bf a)\\\\
log_9\left( \sqrt[3]{y^2+y} \right)\implies log_9\left[ (y^2+y)^{\frac{1}{3}} \right]\implies \cfrac{1}{3}log_9(y^2+y)
\\\\\\
\cfrac{1}{3}log_9[y(y+1)]\implies \cfrac{1}{3}\left[~log_9(y)~+~log_9(y+1) ~ \right]
\\\\\\
\cfrac{1}{3}log_9(y)~~+~~\cfrac{1}{3}log_9(y+1)


\bf b)\\\\
log_4\left( \frac{a^2b}{\sqrt{c}} \right)\implies log_4(a^2b)~-~log_4(\sqrt{c})\implies log_4(a^2b)~-~log_4(c^{\frac{1}{2}})
\\\\\\\
[~log_4(a^2)~+log_4(b)~]~~-~~\cfrac{1}{2}log_4(c)\\\\\\ log_4(a^2)+log_4(b)-\cfrac{1}{2}log_4(c)
7 0
4 years ago
Molly shot 20 baskets in 4 minutes. Nico shot 42 baskets in 6 minutes. How many more baskets did Nico shoot per day minute?
Zarrin [17]
Nico shot 2 baskets per mintue
8 0
3 years ago
Read 2 more answers
Find the area of the shaded region.
sveticcg [70]

Answer:

12.86 sq ft

Step-by-step explanation:

Find area of square and subtract out area of semi-circle; the diameter of the semi-circle equals the side of the square, which is 4 so radius is 2

A(square) = 4 x 4 = 16

A(semi-circle) = πr²/2

= 4π/2 or 2π

Area of Shaded Region = 16-3.14 which is 12.86

7 0
3 years ago
Which number makes this equation true?<br><br>5 x (3 x 2)= 5 x ?
Bond [772]

Answer:

6

Step-by-step explanation:

7 0
3 years ago
Find the exact area of a circle having the given circumference.
blagie [28]

Answer:

<h2>A = 2.25π</h2>

Step-by-step explanation:

The formula of an area of a circle:

A=\pi r^2

r - radius

The formula of a circumference of a circle:

C=2\pi r

We have:

C=3\pi

Substitute:

2\pi r=3\pi            <em>divide both sides by 2π</em>

r=1.5

Substitute:

A=\pi(1.5)^2=2.25\pi

3 0
3 years ago
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