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3 years ago

which telecommunications service allows internet and telephone service to work over the same phone line

Computers and Technology

1 answer:

kifflom [539]3 years ago

6 0

Answer:

DSL telecommunications service allows internet and telephone service to work over the same phone line

Explanation:

DSL means Digital Subscriber Line

This provides “high speed internet connection” through “telephone line”. The beauty of it is that it does not require any “special wires” in additional. Only the “modem” will be additional part of expenses and a separate installation. But this would be provided by the “Service provider” itself.

In the classical method of using internet via phone will allow either a call to be made or internet to be browsed. Once a call comes in, the internet gets disconnected. But here it has overcome the disadvantage and now both phone calls and internet can be used simultaneously.

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What is Colby Knox known for?

fiasKO [112]

Answer:The School in the Woods. Colby Knox is known for his work on The School in the Woods

Explanation:

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2 years ago

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BigorU [14]

I’m not sure what you’re asking, what about a presentation? Reply back to this and lmk so I can figure it out for ya!!

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3 years ago

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A network administrator is planning redundant devices and cabling in a switched network to support high availability. Which bene

a_sh-v [17]

Answer:

Redundant paths can be available without causing logical Layer 2 loops.

Explanation:

Spanning Tree Protocol is used to allow redundancy in the Layer 2 switched networks without creating cycles/circles also called loops.
These loops are called physical loops.
When two parts of the switched network are connected via two or more Layer 2 switches this result in a loop.
This affects the performance of the network as the result of broadcast packets flooding.
STP puts one port of the switch to forward mode and the rest of the ports within the same part of the network to the blocking mode to avoid broadcast packet flooding. STP puts all the ports that are allowing redundant paths to block mode and the one port that is left after this is placed in forward mode.
Spanning Tree Algorithm is used by STP to determine the optimal path of switch to the network.
Bridge Protocol Data Units are used to share the information about the optimal path determined by the spanning tree algorithm with other switches.
This information helps STP to eliminate the redundant paths.
So this is how STP tracks all the links in the switched network and eliminates redundant loops by allowing only one active path to the destination while blocking all other paths.

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3 years ago

Prove that any amount of postage greater than or equal to 64 cents can be obtained using only 5-cent and 17-cent stamps?

elixir [45]

Let P(n) be "a postage of n cents can be formed using 5-cent and 17-cent stamps if n is greater than 63".Basis step: P(64) is true since 64 cents postage can be formed with one 5-cent and one 17-cent stamp.Inductive step: Assume that P(n) is true, that is, postage of n cents can be formed using 5-cent and 17-cent stamps. We will show how to form postage of n + 1 cents. By the inductive hypothesis postage of n cents can be formed using 5-cent and 17-cent stamps. If this included a 17-cent stamp, replace this 17-cent stamp with two 5-cent stamps to obtain n + 1 cents postage. Otherwise, only 5-cent stamps were used and n 65. Hence there are at least three 5-cent stamps forming n cents. Remove three of these 5-cent stamps and replace them with two 17-cent stamps to obtain n + 1 cents postage.Hence P(n + 1) is true.

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3 years ago

g Create a package named lab7 (no spaces, ALL in lowercase) where you will place your lab files. Write a class FilterWith with a

sweet [91]

Answer:

See explaination

Explanation:

import java.util.ArrayList;

import java.util.Scanner;

public class ListFilter

{

public static void filterRange(ArrayList<Integer> list,int min, int max)

{

ArrayList<Integer> listNew=new ArrayList<Integer>();

for(int i=0;i<list.size();i++)

{

if(list.get(i)>=min && list.get(i)<=max) //Checking if element is between min and max

{

listNew.add(list.get(i));

}

list.removeAll(listNew); //removing all elements from list.

}

public static void main(String[] args)

{

ArrayList<Integer> list=new ArrayList<Integer>();

list.add(4);

list.add(7);

list.add(9);

list.add(2);

list.add(7);

list.add(5);

list.add(3);

list.add(5);

list.add(1);

list.add(7);

list.add(8);

list.add(6);

list.add(7);

Scanner sc=new Scanner(System.in);

System.out.println("Enter min : ");

int min=sc.nextInt();

System.out.println("Enter Max : ");

int max= sc.nextInt();

filterRange(list, min, max);

//Displaying new List

for(int i=0;i<list.size();i++)

{

System.out.print(list.get(i)+" ");

}

3 0

3 years ago