<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
The formula to find the volume of cube
cube = s^3
Therefore volume is equal to I^3
The second cube has 4x the First cube
4 × (I^3) = 4 ×I^3
Total volume of the second cube= 4I^3 cm3
Fact: the density(mass ÷ volume) of aluminium is 2.40g/cm3
Making mass the subject of the formula:
D = M ÷ V
(Times volume to remove deno minator)
Mass = Density × Volume
Mass = 2.40 × 4I ^3
Mass = 8.40I^3
By physics
weight= m × g
where
M = mass
g = acceleration due to gravity (= 9.8)
W = 8.40 I^3 × 9.8
Weight of aluminium = 82.32I^3
<h3>
Answer: 3 m/s^2</h3>
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According to Newton's Second Law, we know that
F = m*a
where F is the force applied, m is the mass and 'a' is the acceleration.
We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.
Plug in F = 35 and a = 5 to find m
F = ma
35 = m*5
35/5 = m
7 = m
m = 7
The object has a mass of 7 kg
Our equation F = ma updates to F = 7a
Now plug in the force F = 21 to find 'a'
F = 7a
21 = 7a
21/7 = a
3 = a
a = 3
The acceleration will be 3 m/s^2
Notice how a smaller force applied means that the acceleration has also gone down as well.
