Answer:
So the height is 12
Step-by-step explanation:
Let W be the width
Let W- 4 be the height
W2 +(W-4)2 = 400
So: W2 -4W-192 =0
One uses the quadratic solution:
W = (4 + (16 + 4*192).5)/2 = 16
The relations are domain and range
Just subsitute 8 for n
1/2(8)^2-1/2(8)
1/2(64)-4
32-4
28
D
Answer:
type 2 in the first box,
13/4 in the second box, and
-9/8 in the third one
Step-by-step explanation:Notice that you are asked to write the following quadratic expression in vertex form, so you need to find the "x" value of the vertex, and then the "y" value of the vertex:
![x_{vertex}= -b/2a](https://tex.z-dn.net/?f=x_%7Bvertex%7D%3D%20-b%2F2a)
Which in our case is: -13/4
and the value of the y for the vertex is obtained using the functional expression when x equals -13/4:
![f(-13/4)= -9/8](https://tex.z-dn.net/?f=f%28-13%2F4%29%3D%20-9%2F8)
Then your expression for this quadratic should be:
![f(x)=2\,(x+\frac{13}{4} )^2+(-\frac{9}{8})](https://tex.z-dn.net/?f=f%28x%29%3D2%5C%2C%28x%2B%5Cfrac%7B13%7D%7B4%7D%20%29%5E2%2B%28-%5Cfrac%7B9%7D%7B8%7D%29)
Then type 2 in the first box, 13/4 in the second box, and -9/8 in the third one
Answer:
2,800 Books to be the same.