Here are the steps I would use to complete this question.
Blue can be 1/10 and yellow can be 3/10 or other way around.
Answer:
SEE BELOW
Step-by-step explanation:
A: Yes, it is 18.80%. Sample Mean= 135, Sample Standard deviation= 25/sq rt of 10 = 7.906, normalcdf(142, 999999, 135, 7.906) = .18796 × 100 = 18.796 = 18.80%
B: If we increase the sample size to 50, then, due to the Central Limit Therme, there should be less variation within the data (it should point to a more clear center). Sample Mean= 135, Sample Standard deviation= 25/sq rt of 50 = 3.535, normalcdf(142, 999999, 135, 3.535) = .02385 × 100 = 2.385 = 2.39%
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Let t represent Yesenia's score on the third test. If her average is 79 for the three tests, then]
.. (91 +73 +t)/3 = 79
.. 164 +t = 237
.. t = 237 -164 = 73
Yesenia's score on the third test is 73.
_____
You can also look at points relative to the average. On her first test, Yesenia scored 12 points above her average. On her second test, 6 points below her average. In order to make the total relative to the average come out to be zero, she must have also scored 6 points below average on the third test, or 79 -6 = 73.
