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3 years ago

What is 8.05x10^-5 in standard notation

Mathematics

1 answer:

Marina CMI [18]3 years ago

6 0

Answer: 0.0000805

Step-by-step explanation:

You move the decimal 5 places to the left of 8.05.

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Jon has to pay $7.50 admission for the skating rink and $1.50 per hour to rent rollerblades. Write an equation for the cost (y)

Nata [24]

Answer:

y = 7.50 + 1.50x

Step-by-step explanation:

The admission costs $7.50 and after x hours Jon has to pay $1.50*x. Then the cost y in dollars is

y = 7.50 + 1.50x where x is the number of hours.

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3 years ago

()) Solve for w.<br><br> W times 1/2= 7/8

nikklg [1K]

W equals 14/8 is the correct answer

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2 years ago

This week, 300 tickets were sold to the school play. This is 120 percent of the number of tickets sold last week for the school

skad [1K]

Answer:

the awnser is 250 i took the test and got it correct

Step-by-step explanation:

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3 years ago

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Andrea is shopping for items for her pet sitting business because the store is having a sale where everything in the store

frutty [35]

Answer:

the answer is the first one

Step-by-step explanation:

39.99 rounded up is 40.00

19.99 rounded up is 20.00

40.00*0.05 = 2, 40-2 = 38

20.00*0.15 = 3, 20-3 = 17*.05 = 0.85, 17-0.85 = 16.15

38+16.15 = 54.15

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3 years ago

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A simple random sample of 100 observations was taken from a large population. The sample mean and the standard deviation were de

olga2289 [7]

Answer:

Se=1.2

Step-by-step explanation:

The standard error is the standard deviation of a sample population. "It measures the accuracy with which a sample represents a population".

The central limit theorem (CLT) states "that the distribution of sample means approximates a normal distribution, as the sample size becomes larger, assuming that all samples are identical in size, and regardless of the population distribution shape"

The sample mean is defined as:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

And the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

Let X denotes the random variable that measures the particular characteristic of interest. Let, X1, X2, …, Xn be the values of the random variable for the n units of the sample.

As the sample size is large,(>30) it can be assumed that the distribution is normal. The standard error of the sample mean X bar is given by:

$Se=\frac{\sigma}{\sqrt{n}}$

If we replace the values given we have:

$Se=\frac{12}{\sqrt{100}}=1.2$

So then the distribution for the sample mean $\bar X$ is:

$\bar X \sim N(\mu=80,Se=1.2)$

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3 years ago