Hi
f(x) = g(x) if -x²+3x-2 - ( -x+1) = 0
-x² +3x-2 +x-1 = 0
-x² +4x -3 = 0
To solve, tou have to use the general method of resolution of a quadratic fonction.
To determine if it's has a solution in R, let's calculate Δ
Δ = (4)² - 4 * (1) *(-3)
Δ = 16 +12
Δ= 28
as Δ≥ 0 so the function allow two solution within R
so S 1 = ( -4 +√28) / 2 S 2 = (-4 -√28 ) /2
S1 = ( -4 + 2√7) /2 S2 = (-4 - 2√7) /2
S1 = (2 (-2 +√7) /2 S2 2 (-2 -√7) /2
S1 = -2 +√7 S2 = -2 -√7
So the two function are equal twice. one for x = -2 +√7 and second x = -2-√7
Answer:
15/50
Step-by-step explanation:
5*3=15
5*10=50
so 15/50.
I believe if I have done this right the answer will be 1352
Answer:
Step-by-step explanation:
Cos θ =<u> u*v </u>
IuI *IvI
u * v = 7*(-1) + (-2)*2
= -7 - 4
= -11
IuI = 
= 
= 
I vI = 
= 
= 
Cos θ = 
= 
Cos θ = -0.68
θ = 132.5°
Alright sure:
Q5: ∠3
Q6: ∠1
Q7: ∠2
Q8: x = 25
Q9: x = 63
For Questions 8 and 9 what I did was find out the supplementary angle adjacent to the exterior angle.
8: 180° in a supp. angle. So 180-105 = 75. To make a triangle it has to be 180°. So 180 - 75-80 = 25 So x=25
9: 180° in a supp. angle. So 180-135 = 45. To make a triangle it has to be 180°. So 180 - 45-72 = 63. So x=63
Let me know if you don't understand that. If you don't get it I'll explain it further for you.
