Solve for x. −46 x=25

Estimate how many times larger 7 x 10^10 is than 13 x 10^8.

Tpy6a [65]

The answer to this equation is A) 50 times larger

4 0

3 years ago

Read 2 more answers

Find the intersection points of the linear and quadratic functions shown below f(x)=2x-5 g(x)= x2+2x-21

Mice21 [21]

Answer:

$(-4,-13)$ and $(4,3)$ the intersection points.

Step-by-step explanation:

Intersection point of two functions is a common point which satisfies both the functions.

Given functions are,

$f(x)=2x-5$

$g(x)=x^2+2x-21$

For a common point of these functions,

$f(x)=g(x)$

$2x-5=x^2+2x-21$

$-5=x^2-21$

$0=x^2-16$

$x^2=16$

$x=-4,4$

For $x=-4$ ,

$f(-4)=g(-4)=2(-4)-5$

$=-13$

For $x=4$ ,

$f(4)=g(4)=2(4)-5$

$=3$

Therefore, $(-4,-13)$ and $(4,3)$ the intersection points.

3 0

3 years ago

As part of a class project, a university student surveyed the students in the cafeteria lunch line to look for a relationship be

Vedmedyk [2.9K]

Answer:

0.63

Step-by-step explanation:

To get the relative frequency of students with red hair, we need to find the relative frequency of students with red hair from the students with gray eyes.

Since we already know that the total number of students with gray eyes is 35 and the number of red hair students with gray eye is 22

The formula we will use to calculate the relative frequency will be

The relative frequency of students with red hair = Total students of red hair with gray eyes divide by total number of gray eye students

22 ÷ 35 = 0.628 ≅ 0.63

6 1

3 years ago

There is a bag filled with 4 blue, 3 red and 5 green marbles.

bearhunter [10]

Answer:

1/11

Step-by-step explanation

There are 12 marbles in the bag. When we first pick we have 4 blue marbles. So 4 blue marbles/12 random marbles. When we pick blue and noted, there are 3 marbles in the bag because of we didn't put it back. So when we choose again there are 11 marbles and 3 blue marbles in the bag. Choosing a blue one case is 3/11.

The last part of this case is happening as a chain. So we need to multiply our two answers.

=4/12*3/11

=1/3*3/11

=1/11

7 0

3 years ago

Consider the line shown on the graph. Enter the

Semenov [28]

<h2>Solution -</h2>

From the graph, we concluded that line passes through the points (0, 3) and (1, 4) respectively.

So, slope of the line (m) passing through the points (a, b) and (c, d) is

m = d - b/ c - a

<h3>So, on substituting the values, we get </h3>

m = 4 - 3 / 1 - 0 = 1/1 = 1

Also, line makes an intercept of 3 units in positive direction of y - axis.

So, c = 3

<h3>So, Equation of line is given by</h3>

y = mx + c

y = 1 × x + 3

<h3>Alternative Method :-</h3>

We know, Equation of line passing through the points (a,b) and (c, d) is given by

y - b = d - b / c - a (x - a)

a = 0

b = 3

c = 1

d = 4

<h3>So, on substituting these values in above result, we get :-</h3>

y - 3 = 4 - 3 /1 - 0 ( x - 0 )

y - 3 = 1/1 ( x - 0 )

y - 3 = x

<h3>Different forms of equations of a straight line :-</h3>

1. Equations of horizontal and vertical lines

Equation of line parallel to x - axis passes through the point (a, b) is y = b.

Equation of line parallel to y - axis passes through the point (a, b) is x = a.

<h3>2. Point-slope form equation of line</h3>

Equation of line passing through the point (a, b) having slope m isy - b = m(x - a)

<h3>3. Slope-intercept form equation of line</h3>

Equation of line which makes an intercept of c units on y axis and having slope m is y = mx + c.

<h3>4. Intercept Form of Line</h3>

Equation of line which makes an intercept of a and b units on x - axis and y axis respectively is x/a + y/b = 1.

<h3>5. Normal form of Line</h3>

Equation of line which is at a distance of p units from the origin and perpendicular makes an angle B with the positive X-axis is x cosB + y sinB = p.

<h2 />

8 0

2 years ago