The value (9/10)*81 is greater than (5/6)*81
<h3>How to determine the greater value?</h3>
The values are given as:
(5/6)*81 and (9/10)*81
Remove the common factor in both values
So, we have:
5/6 and 9/10
Convert to decimals
0.83 and 0.9
0.9 is greater than 0.83
Hence, (9/10)*81 is greater than (5/6)*81
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Answer:
Part 1) The domain of the quadratic function is the interval (-∞,∞)
Part 2) The range is the interval (-∞,1]
Step-by-step explanation:
we have

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)
step 1
Find the domain
The domain of a function is the set of all possible values of x
The domain of the quadratic function is the interval
(-∞,∞)
All real numbers
step 2
Find the range
The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.
we have a vertical parabola open downward
The vertex is a maximum
Let
(h,k) the vertex of the parabola
so
The range is the interval
(-∞,k]
Find the vertex

Factor -1 the leading coefficient

Complete the square


Rewrite as perfect squares

The vertex is the point (7,1)
therefore
The range is the interval
(-∞,1]
Affect the size, shape, or phase of a substance.
Answer:
20 in³
Step-by-step explanation:
Area of a triangle is half the base times the perpendicular height:
A=0.5bh
=0.5*10*4
=20
Answer:
x<15, probably
Step-by-step explanation:
maybe multiply 2 to each side to eliminate the fraction. so 3x+15<60. subtract 15 to isolate the variable term so 3x<45. divide by 3 to isolate x so x<15. check the work. is the inequality true for all values of x less than 15? let's try the first possible integer value, 14, to be sure. 3(14)+15= 57. so 57/2<30. now 57/2 is 28.5 and 28.5<30 so it seems right