To get the answer you must see how many times 7 can go in 114
One possible divided is the number 1236.
If 5 went into 1235 the quotient would be exactly 247. However, there needs to be a remainder. So let's just change the number to 1236. Then, there will be a remainder of 1.
The answer is: x² – 6x + 9 = 0 .
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Explanation:
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Given: (x – 3)² = 0 ; write as: general form: "ax² + bx + c = 0"; a ≠ 0 .
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Note: </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ;
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Rewrite: (x – 3)² = 0 ; →
as: x² – 6x + 9 = 0 ; which is our answer.
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→ x² – 6x + 9 = 0 ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 "; (a ≠ 0) ;
→ in which:
a = 1 (implied coefficient, since anything multiplied by "1" is that same value);
b = -6;
c = 9
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Answer:
its b
Step-by-step explanation:
If we deal with Natural numbers then the range is
1 ≤ p ≤ 5
