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3 years ago

8

In a hydraulic jack, the pipe below the load has an area of 4 m2, and the pipe through which the input force transmits has an ar

ea of 0.1 m2. What input force is necessary to balance a load of 9,000 N?

2 answers:

soldi70 [24.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

Since the pipe is an enclosed container, we would apply Pascal's law which states that a pressure applied to a fluid in a closed container is transmitted equally to every point of the fluid and the walls of the container,

This means that pressure at input = pressure at output

Pressure = force /area

Input force = unknown

Input area = 0.1 m²

Output force = 9000N

Output area = 4m²

Therefore

Input force/0.1 = 9000/4

Input force = 0.1 × 9000 /4 = 225N

vodomira [7]3 years ago

3 0

Answer:

The input force needed is 225 Newtons

Step-by-step explanation:

From hydraulic pressure laws, we have that the pressure at the same level throughout the body of a fluid is equal.

This means that for the Hydraulic Jack, input pressure = output pressure

Recall,Pressure is a ratio of force and area

i.e pressure = Force / Area

For the hydraulic jack to work properly, the pressure at the input end must be equal to the pressure at the output end.

$\frac{F_{1}}{A{1}} = \frac{F_{2}}{A_{2}}$

$\frac{9000}{4}=\frac{Force}{0.1}$

From this we can compute that the Input force = 225 Newtons

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4 years ago

Rationalise the denominator of:<br>1/(√3 + √5 - √2)

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Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

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<h3><u>More Identities to </u><u>know:</u></h3>

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$\purple{\boxed{\tt{ {(x + y)}^{3} = {x}^{3} + 3xy(x + y) + {y}^{3}}}}$

$\purple{\boxed{\tt{ {(x - y)}^{3} = {x}^{3} - 3xy(x - y) - {y}^{3}}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2})}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} - {(x - y)}^{2} = 4xy}}}$

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3 years ago