Answer:
A normal model is a good fit for the sampling distribution.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
The information provided is:
<em>N</em> = 675
<em>X</em>₁ = bodies with low vitamin-D levels had weak bones
<em>n</em>₁ = 82
<em>p</em>₁ = 0.085
<em>X</em>₂ = bodies with regular vitamin-D levels had weak bones
<em>n</em>₂ = 593
<em>p</em>₂ = 0.01
Both the sample sizes are large enough, i.e. <em>n</em>₁ = 82 > 30 and <em>n</em>₂ = 593 > 30.
So, the central limit theorem can be applied to approximate the sampling distribution of sample proportions by the Normal distribution.
Thus, a normal model is a good fit for the sampling distribution.
Given triangle ABC with coordinates A(−5, 4), B(−5, 1), and C(−7, 0), and its image A′B′C′ with A′(−1, 0), B′(−4, 0), and C′(−5,
UNO [17]
Answer:
y = x+5
Step-by-step explanation:
A graph can help.
__
The line of reflection will pass through the midpoints of AA' and BB'.
The midpoint of AA' is ((-5, 4) +(-1, 0))/2 = (-3, 2)
The midpoint of BB' is ((-5, 1) +(-4, 0))/2 = (-4.5, 0.5)
The slope of the line through these points is ...
Δy/Δx = (2 -0.5)/(-3-(-4.5)) = 1.5/1.5 = 1
Then the y-intercept can be found from
y = x + b
2 = -3 + b
5 = b
So, the line of reflection is ...
y = x + 5
The triangle has a base of 7 so 1/2 the base is 3.5.
The height = 7.5 (from graphic)
Area of "left triangle" = 3.5*7.5 / 2 =
<span>
<span>
<span>
13.125
</span>
</span>
</span>
The entire triangle area = 2 * 13.125 =
26.25
Triangle perimeter both legs = 16.6 + base (7) = 23.6
3(5)-15+10(7)-2(5)
15-15+70-10
=60
The answer is 60