1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vodomira [7]
3 years ago
11

Volume of a triangular prism

Mathematics
2 answers:
Strike441 [17]3 years ago
6 0
The formula is the area of the base times the height.<span>

<span /></span>
3241004551 [841]3 years ago
6 0
Is x because no variables are given
You might be interested in
How much interest is earned on $2,700 in one year if it is invested at 3%?
Natalka [10]
$81 is earned by investing $2700 in one year at 3%.
3 0
3 years ago
7) Solve the following system of equations below algebraically using substitution.
Pani-rosa [81]

Answer:

x = 3.25

y =4.75

Step-by-step explanation:

In order to Solve the following system of equations below algebraically using substitution method we say that;

let;

8x - 4y = 7 ..................... equation 1

x + y = 8.......................... equation 2

from equation2

x + y = 8.......................... equation 2

x = 8 - y.............................. equation 3

substitute for x in equation 1

8x - 4y = 7 ..................... equation 1

8(8-y) - 4y = 7

64-8y-4y=7

64-12y=7

collect the like terms

64-7 = 12y

57= 12y

divide both sides by the coefficient of y which is 12

57/12 = 12y/12

4.75 = y

y =4.75

put y = 4.75 in equation 3

x = 8 - y.............................. equation 3

x = 8 -4.75

x = 3.25

to check if your answer is correct, put the value of x and y in either equation 1 or 2

from equation 2

x + y = 8.......................... equation 2

3.25 + 4.75 =8

8=8.................... proved

8 0
3 years ago
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x3 − 6x2 − 15x + 4 (a) Find the interval on which
kozerog [31]

Answer:

a) The function, f(x) is increasing at the intervals (x < -1.45) and (x > 3.45)

Written in interval form

(-∞, -1.45) and (3.45, ∞)

- The function, f(x) is decreasing at the interval (-1.45 < x < 3.45)

(-1.45, 3.45)

b) Local minimum value of f(x) = -78.1, occurring at x = 3.45

Local maximum value of f(x) = 10.1, occurring at x = -1.45

c) Inflection point = (x, y) = (1, -16)

Interval where the function is concave up

= (x > 1), written in interval form, (1, ∞)

Interval where the function is concave down

= (x < 1), written in interval form, (-∞, 1)

Step-by-step explanation:

f(x) = x³ - 6x² - 15x + 4

a) Find the interval on which f is increasing.

A function is said to be increasing in any interval where f'(x) > 0

f(x) = x³ - 6x² - 15x + 4

f'(x) = 3x² - 6x - 15

the function is increasing at the points where

f'(x) = 3x² - 6x - 15 > 0

x² - 2x - 5 > 0

(x - 3.45)(x + 1.45) > 0

we then do the inequality check to see which intervals where f'(x) is greater than 0

Function | x < -1.45 | -1.45 < x < 3.45 | x > 3.45

(x - 3.45) | negative | negative | positive

(x + 1.45) | negative | positive | positive

(x - 3.45)(x + 1.45) | +ve | -ve | +ve

So, the function (x - 3.45)(x + 1.45) is positive (+ve) at the intervals (x < -1.45) and (x > 3.45).

Hence, the function, f(x) is increasing at the intervals (x < -1.45) and (x > 3.45)

Find the interval on which f is decreasing.

At the interval where f(x) is decreasing, f'(x) < 0

from above,

f'(x) = 3x² - 6x - 15

the function is decreasing at the points where

f'(x) = 3x² - 6x - 15 < 0

x² - 2x - 5 < 0

(x - 3.45)(x + 1.45) < 0

With the similar inequality check for where f'(x) is less than 0

Function | x < -1.45 | -1.45 < x < 3.45 | x > 3.45

(x - 3.45) | negative | negative | positive

(x + 1.45) | negative | positive | positive

(x - 3.45)(x + 1.45) | +ve | -ve | +ve

Hence, the function, f(x) is decreasing at the intervals (-1.45 < x < 3.45)

b) Find the local minimum and maximum values of f.

For the local maximum and minimum points,

f'(x) = 0

but f"(x) < 0 for a local maximum

And f"(x) > 0 for a local minimum

From (a) above

f'(x) = 3x² - 6x - 15

f'(x) = 3x² - 6x - 15 = 0

(x - 3.45)(x + 1.45) = 0

x = 3.45 or x = -1.45

To now investigate the points that corresponds to a minimum and a maximum point, we need f"(x)

f"(x) = 6x - 6

At x = -1.45,

f"(x) = (6×-1.45) - 6 = -14.7 < 0

Hence, x = -1.45 corresponds to a maximum point

At x = 3.45

f"(x) = (6×3.45) - 6 = 14.7 > 0

Hence, x = 3.45 corresponds to a minimum point.

So, at minimum point, x = 3.45

f(x) = x³ - 6x² - 15x + 4

f(3.45) = 3.45³ - 6(3.45²) - 15(3.45) + 4

= -78.101375 = -78.1

At maximum point, x = -1.45

f(x) = x³ - 6x² - 15x + 4

f(-1.45) = (-1.45)³ - 6(-1.45)² - 15(-1.45) + 4

= 10.086375 = 10.1

c) Find the inflection point.

The inflection point is the point where the curve changes from concave up to concave down and vice versa.

This occurs at the point f"(x) = 0

f(x) = x³ - 6x² - 15x + 4

f'(x) = 3x² - 6x - 15

f"(x) = 6x - 6

At inflection point, f"(x) = 0

f"(x) = 6x - 6 = 0

6x = 6

x = 1

At this point where x = 1, f(x) will be

f(x) = x³ - 6x² - 15x + 4

f(1) = 1³ - 6(1²) - 15(1) + 4 = -16

Hence, the inflection point is at (x, y) = (1, -16)

- Find the interval on which f is concave up.

The curve is said to be concave up when on a given interval, the graph of the function always lies above its tangent lines on that interval. In other words, if you draw a tangent line at any given point, then the graph seems to curve upwards, away from the line.

At the interval where the curve is concave up, f"(x) > 0

f"(x) = 6x - 6 > 0

6x > 6

x > 1

- Find the interval on which f is concave down.

A curve/function is said to be concave down on an interval if, on that interval, the graph of the function always lies below its tangent lines on that interval. That is the graph seems to curve downwards, away from its tangent line at any given point.

At the interval where the curve is concave down, f"(x) < 0

f"(x) = 6x - 6 < 0

6x < 6

x < 1

Hope this Helps!!!

5 0
3 years ago
Make a number that has a 6 that is 10 times the value of the digit 6 in 165,438 Comparing digits in whole numbers
Ipatiy [6.2K]

Answer:

An example of such number is 1,645,378 ( The value of 6 here is 600,000)

Step-by-step explanation:

Here, we want to compare digits in whole

numbers.

The value of 6 in 165,438 = 60,000

Now, we want a number that is 10 times the value of 6 here

10 times the value of 6 here will be 10 * 60,000 = 600,000

So we want a number which has the value of 6 in it as 600,000

The number in this case as an example can be ;

1,645,378

3 0
3 years ago
A 3.5 ft by 5.5 ft mirror is placed in a wooden frame. What is the area of the frame
Alborosie

Answer:

19.25ft

Step-by-step explanation:

area = length x width so 3.5 x 5.5 = 19.25

8 0
3 years ago
Read 2 more answers
Other questions:
  • Find the circumference of a circle who's diameter is 4
    7·1 answer
  • Based on the current eligibility requirement, a study conducted in 2004 showed that federal spending on entitlement programs, pa
    5·2 answers
  • Dana has n quarters. Ivan has 2 fewer than 3 times the number of quarters Dana has. The expression n + 3 n−2 gives the number of
    8·1 answer
  • Pi/6 is the reference angle for:<br><br> 3pi/6<br><br> 5pi/6<br><br> 13pi/6<br><br> 8pi/6
    6·1 answer
  • Solve 2^(3x-4)=5 round to the nearest ten-thousandth
    11·2 answers
  • There are 10 marbles in a bag 1/5 are red and the others are blue. what is the ratio of red to blue?
    10·1 answer
  • Rewrite the following equation in slope-intercept form.<br> 6x + 13y = -10
    7·2 answers
  • Hello! Please help. <br> "Find the error &amp; explain why it is wrong."
    11·1 answer
  • A man took out a $44,000 construction loan to remodel a house. The loan rate is 8.5% simple interest per year to be repaid in th
    5·1 answer
  • Simplify the expression:<br> 7r2+5r2+9r
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!