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earnstyle [38]
3 years ago
14

The graph of a linear function is shown which word describes the slope of the line the choices and graph is below

Mathematics
2 answers:
kumpel [21]3 years ago
7 0
The graph is negative because it goes down to the right, meaning that it is decreasing. I hooe this helps!
aliya0001 [1]3 years ago
4 0
<h2>Answer </h2>

negative

<h2>Explanation </h2>

Let's find the slope of our line using the slope formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

where

m is the slope of the line

(x_{1},y_{1}) are the coordinates of the first point on the line

(x_{2},y_{2}) are the coordinates of the second point

From the graph we can get the points (-2, 1) and (2, -1), so x_{1}=-2, y_{1}=1, x_{2}=2, and y_{2}=-1. Let's replace the values in our formula to find m:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{-1-1}{2-(-2)}

m=\frac{-2}{2+2}

m=\frac{-2}{4}

m=-\frac{2}{4}

m=-\frac{1}{2}

The slope of the graph of the linear function is -\frac{1}{2}; since -\frac{1}{2} is a negative number, the slope of the graph is negative.

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Answer:

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Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

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The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

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