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2 years ago

14

Use the data to answer the following question.

1 answer:

PtichkaEL [24]2 years ago

4 0

Answer: a

Step-by-step explanation:

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A square has an area of 150 square centimeters. Which of the

Sergio [31]

Answer:

C) 12.2 cm

Step-by-step explanation:

To find the area of a square, you multiply length and width, which for a square, are the same. So to find the length of one of its sides, you have to take the square root of the area.

$L^{2} = 150\\\\L=\sqrt{150} \\L= 12.2\\$

7 0

2 years ago

Question in picture above

Gnesinka [82]

Answer:

B.(12,5)

Step-by-step explanation:

Hope this helps :)

5 0

3 years ago

Which is an asymptofe of the graph the function y=cot(x-2π/3)

Shalnov [3]

Hello.

C) x=4π/3

The variable x in the cotangent argument has a unit coefficient, so the period is π, just as it is in the parent function cot(x).

Can you graph y = cot(x)? By subtracting the constant π/6 from the argument, that graph is translated to the right by π/6. Just as with cot(x), it is decreasing everywhere.

Have a nice day

5 0

3 years ago

The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

Anettt [7]

Answer:

1) The size of the colony after 4 days is 6553 mosquitoes

2) After $t = 4.9\ days$

Step-by-step explanation:

To answer this question you must use the growth formula

$N = N_0e ^ {kt}$

Where

$N_0$ is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and $N_0=1000$ then N = 1600

Then we use these values to find k.

$1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47$

Now that we know k we can find the size of the colony after 4 days.

$N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes$

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

$10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days$

6 0

2 years ago

A marble is randomly selected from a bag. The probability of selecting a marble with dots on it is 0.2. The probability of selec

marin [14]

Answer:

0.5

Step-by-step explanation:

Let D be the event of selecting a marble with dots.

Let P be the event of selecting a purple marble.

The probability of selecting a marble with dots, P(D)=0.2

The probability of selecting a marble that is both purple and has dots, $P(D \cap P)=0.1$

We want to determine the probability of selecting a purple marble given that the marble has dots on it, P(P|D)

By the definition of conditional probability:

$P(P|D)= \dfrac{P(P \cap D)}{P(D)} \\= \dfrac{0.1}{0.2}\\ =0.5$

The probability of selecting a purple marble given that the marble has dots on it is 0.5.

4 0

2 years ago