Hello,
Please, see the attached files.
Thanks.
x^2 - 7x + 15
_________________
(x+4)/ x^3 - 3x^2 - 13x + 78
- x^3 + 4x^2
----------------
- 7x^2 - 13x
- - 7x^2 - 28x
------------------
15x + 78
- 15x + 60
-------------
18
remainder = 18
Answer:
3/5 has the smallest denominator
Step-by-step explanation:
Question:
There exist infinitely many common fractions a/b , where a > 0 and b > 0 and for which 3/5 < a/b< 2/3. Of these common fractions, which has the smallest denominator? Express your answer as a common fraction.
Solution
A Common fraction is a rational number written in the form: a/b. Where a and b are both integers.
The denominator and numerator in this case are greater than zero. That is, they are non zeros.
The least common denominator (LCD) of two non- zero denominators is the smallest whole number that is divisible by each of the denominators.
To find the smallest denominator between 3/5 and 2/3, we would convert the fractions to equivalent fractions with a common denominator by finding their LCM (lowest common multiple).
When comparing two fractions with like denominators, the larger fraction is the one with the greater numerator and the smaller fraction is one with the smaller numerator.
In our solution after comparing, the smaller fraction would have the smallest denominator.
Find attached the solution.
Answer:
Malcolm would fill 8 bags of rice.
Step-by-step explanation:
The size of the container of rice = 5
pounds =
pounds.
Each bag of rice has a capacity of
pounds.
The number of bags of rice that Malcolm fills = 
=
÷ 
=
x 
= 
= 8
Therefore, Malcolm would be able to fill 8 bags of rice.
The graphs that are density curves for a continuous random variable are: Graph A, C, D and E.
<h3>How to determine the density curves?</h3>
In Geometry, the area of the density curves for a continuous random variable must always be equal to one (1). Thus, we would test this rule in each of the curves:
Area A = (1 × 5 + 1 × 3 + 1 × 2) × 0.1
Area A = 10 × 0.1
Area A = 1 sq. units (True).
For curve B, we have:
Area B = (3 × 3) × 0.1
Area B = 9 × 0.1
Area B = 0.9 sq. units (False).
For curve C, we have:
Area C = (3 × 4 - 2 × 1) × 0.1
Area C = 10 × 0.1
Area C = 1 sq. units (False).
For curve D, we have:
Area D = (1 × 4 + 1 × 3 + 1 × 2 + 1 × 1) × 0.1
Area D = 10 × 0.1
Area D = 1 sq. units (True).
For curve E, we have:
Area E = (1/2 × 4 × 5) × 0.1
Area E = 10 × 0.1
Area E = 1 sq. units (True).
Read more on density curves here: brainly.com/question/26559908
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