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a_sh-v [17]
3 years ago
15

jemboy wants to make his 8 meter square pool into a rectangular one by increasing its length by 2m and decreasing its width by 2

m
Mathematics
2 answers:
Maksim231197 [3]3 years ago
8 0
We know that the square pool has area 8 m^2 what we can get it than this square pool has a side length of sqrt8 =2sqrt2 m 
- increasing the length by 2 m will be the length = 2sqrt2 +2 = 2(sqrt2 +1) m
- decreasing the width by 2m will be the width 2sqrt2 -2 = 2(sqrt2 -1) m

so than what is the question or just these all ?
mel-nik [20]3 years ago
3 0
Side = 8m
He increases length by 2m and reduces width by 2m
(a.) New dimensions will be -
Length = 10m and Width = 6m
(b.) Area = length x breadth (or width)
 here we will use the special product (x+y) (x-y)
length = (x+y) and width = (x-y)
area = (8+2) x (8-2)
            8^(2) - 2^(2) 
            = 60
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if the cost price of 10 tables is equal to the selling price of 16 tables , find out the gain or loss percentage​
Dovator [93]

Hi,

To solve this problem, Let us take the LCM of 10 and 16 which will come 80.

Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n

According to the question, CP of 10 tables is equal to the SP of 16 tables, then

the SP of 16 tables will also be ₹ n.

So, SP of 80 tables will be ₹ 5n

So, Loss = CP-SP

→ 8n - 5n = ₹ 3n

Loss%= (3n×100)/8n

Loss%= 37.5%.

Hence the correct answer will be a <u>loss of 37.5%.</u>

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3 years ago
Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )
DedPeter [7]
(a) First find the intersections of y=e^{2x-x^2} and y=2:

2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}

So the area of R is given by

\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx

If you're not familiar with the error function \mathrm{erf}(x), then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line y=1 with y=e^{2x-x^2}.

1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2

So the area of S is given by

\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx
\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve y=e^{2x-x^2} and the line y=1, or e^{2x-x^2}-1. The area of any such circle is \pi times the square of its radius. Since the curve intersects the axis of revolution at x=0 and x=2, the volume would be given by

\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx
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3 years ago
Use the graph to determine the domain and range of the relation, and whether the relation is a function.
Westkost [7]

Answer:

A

Step-by-step explanation:

We can use vertical line test to determine if a relation is a function.

<em>If a vertical line passes the graph at any point only once, then the relation is a function, if there is even 1 line that passes the graph at 2 points, then it is NOT a function.</em>

<em />

The domain is the set of allowed x-values of the function. The range is the set of allowed y-values of the function.

  • Looking at the graph, we see that there are a lot of vertical lines that cuts the graph two times. Suppose x=3, x=4, x= 5 etc. So it is not a function.
  • As for domain, we see that curve swings from x = -8 to x = 8, so the domain is from -8 to 8.
  • As for range, we that the curve stretches all the way from negative infinity to positive infinity, so the range is the set of all real numbers.

Correct answer is A

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spin [16.1K]

Answer:

Equivalent

Step-by-step explanation:

The sets are not equal since computer science is not the same as algebra.

Equal means exactly the same

Equivalent means they have the same number of items in them

If they are equal, they are equivalent

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Katen [24]

Answer:

Step-by-step explanation:

(3, 0) (0, 2)

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y - 0 = -2/3(x - 3)

y = -2/3x + 2

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