We know that the square pool has area 8 m^2 what we can get it than this square pool has a side length of sqrt8 =2sqrt2 m - increasing the length by 2 m will be the length = 2sqrt2 +2 = 2(sqrt2 +1) m - decreasing the width by 2m will be the width 2sqrt2 -2 = 2(sqrt2 -1) m
Side = 8m He increases length by 2m and reduces width by 2m (a.) New dimensions will be - Length = 10m and Width = 6m (b.) Area = length x breadth (or width) here we will use the special product (x+y) (x-y) length = (x+y) and width = (x-y) area = (8+2) x (8-2) 8^(2) - 2^(2) = 60
