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kvasek [131]
3 years ago
7

Y1=9(4x-1), y2=4x+1, and y1 is 393 more than 6 times y2

Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

They are equal. They are both equal to .25

Step-by-step explanation:

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You spin the spinner below once. What is the probability that the arrow will land on 3
Leni [432]

Answer:

how many numbers are there and if there is more of the same number then that will be ur probability

Step-by-step explanation:

8 0
2 years ago
Your friend surveyed 100 people who took either vitamin C, zinc, or Echinacea supplements to prevent getting a cold. The partici
Olin [163]

Answer:

2 people's 2222222222222222

3 0
2 years ago
Which data set has a median of 15? 9, 17, 13, 15, 16, 8, 12 18, 15, 11, 14, 19, 15, 6 7, 16, 14, 16, 11, 7, 17 18, 9, 19, 16, 6,
ivanzaharov [21]

Answer:

The middle number of the data set or average of the two middle numbers in even numbered sets.

Step-by-step explanation:

A median is the middle point of a data set. We order the numbers from least to greatest and find the number directly in the middle of the list. If there are an even number in the set, then we take an average of the middle two.

The data sets are not separated. However, in the sets you have order them least to greatest each. Then count in from both sides to the middle. That number is the middle.

8 0
3 years ago
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
3 years ago
How to solve a mixed number fraction
lesantik [10]
You find a common denominator (the bottom one) and then add the numerator (the top) but you don't add the denominator, you just make it the same
8 0
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