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Ierofanga [76]
3 years ago
15

There are 70 students in the school band. 40% of them are sixth graders, 20% are seventh graders, and the rest are eighth grader

s. How many band members are sixth graders?
Mathematics
1 answer:
Anon25 [30]3 years ago
4 0

Answer:

The number of students in the school band = 70

40% of students in the school band are sixth graders.

20% of students in the school band are seventh graders.

We have to find the number of band members that are sixth graders.

The number of sixth graders in school band are:

40\% of 70

0.40 \times 70

28

Therefore, there are 28 band members that are sixth graders.


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PLEASE HELP ME.<br> THANKS!!!
Veronika [31]

Cos(x) = sin(x + 20o) Use the double cos angle formula

Cos(x) = sin(x)*cos(20) + cos(x)*sin(20) Divide through by cos(x). Tanx = sin(x)/cos(x)

1 = tan(x)*cos(20) + sin(20) Subtract sin(20) from both sides.

1 - sin(20) = tan(x)*cos(20) Calculate the value of 1 - sin(20)

0.65798 = tan(x) * 0.939692 Divide by cos(20)

tan(x) = 0.65795/0.939692

tan(x) = 0.70021 Take the inverse of 0.7) = tan(x)

x = tan-1(0.70021)

x = 35 degrees as expected.

Problem Two

The easiest way to do this is to pick random values and try it. The two acute angles are complementary. So 25 and 65 are random enough.

Let A = 25

Let C = 65

A

Tan(25) = sin(25)/sin(65) ; tan(25) = 0.4663.

sin(25)/sin(65) = 0.4663 Answer

B

Sin(90 - C) = Sin(A)

Tan(90 - A) = Tan(C)

So the question becomes Cos(A) = Tan(C) / sin(A)

Cos(25) = Tan(65)/Sin(25)

0.906 = ? 5.07 This statement isn't true.

C

Sin(65) = Cos(25)/Tan(65)

.906 = 0.4226 C is not the correct answer.

D

D isn't true. The tan does not relate that away. You can find it for yourself.

Cos(A) = Tan(C) You should get 0.906 = 2.14

E

Sin(C) = Cos(A) / Tan(A) I'll leave you to show this is wrong.

Problem 3

The diagram below is for this problem. Cos(x) = 50/100 = 0.5

x = cos-1(0.5)

x = 60 degrees.

Part 2

Sin(60) = opposite / hypotenuse

opposite = sin(60) * hypotenuse

opposite = 86.61 Be sure and round this to whatever the question says to round it to.



4 0
3 years ago
in a recent year one United States dollar was equal to about 82 Japanese yen how many Japanese yen are equal to $1,00 $1,000 $10
Yuki888 [10]
In a recent year, one United States dollar was equal to about 82 Japanese. How many Japanese yen are equal $100?$1,000?$10,000 
<span>Given is: </span>

<span>1 USD = 82 Japanese Yen   </span>

<span>Conversion: </span><span>

1.  100 USD x 82 JY / 1 USD = 8, 200 Japanese Yen</span> <span>
2.  1000 USD x 82 JY / 1 USD = 82, 000 Japanese Yen</span> <span>
3.  10, 000 USD x 82 JY / 1 USD = 820, 000 Japanese Yen</span> 
5 0
3 years ago
X2 + 4x - 9 = 5x + 3<br> O A. 4<br> O B. -3<br> O C. -7<br> O D. 5<br> E. -2<br> F-4
elena-14-01-66 [18.8K]

Answer:

{x}^{2}  + 4x - 9 = 5x + 3 \\  {x }^{2}  - x - 12 \\  {x}^{2}  - 4x + 3x - 12 \\ x(x - 4) + 3(x - 4) \\ (x - 4)(x + 3) \\ x = 4 \: and - 3

7 0
2 years ago
consider the formula F=NM/P, where F represents the fertility of the soil. N represents the amount of nutrients in the soil. M r
Ahat [919]

The options are missing, so i have attached it.

Answer:

Measurement unit for F = (Nutrients • Moisture)/Pollutants.

Option C is correct

Step-by-step explanation:

From the question, we are given the formula; F = NM/P

where;

N is the amount of nutrients in the soil

M is the amount of moisture in the soil.

P is the amount of pollutants in the soil

From the definition of the terms above, the units of the can be expressed as;

N = nutrients

M = moisture

P = pollutants

Thus, the measurement unit for fertility is;

F = NM/P = (Nutrients • Moisture)/Pollutants

6 0
3 years ago
(2x2y4)3<br> Simplify the exponential expression
Gwar [14]

Answer:

6x^2y^4

Step-by-step explanation:

I hope you find this helpfull, btw I really need a brainliests, i just need one more to rank up, nd i would really appriciate it if you let me <em>borror</em> it ;D

4 0
3 years ago
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