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4 years ago

the area of the parallelogram is 90 square inches. what is h, the height in inches of the parallelogram?

Mathematics

1 answer:

Sloan [31]4 years ago

5 0

There are two possible answers:
H=10 inches
L=9 inches
OR
H=9 inches
L=10 inches

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The average price of a home in a certain town was $74,000 in 2012, but home prices

xxTIMURxx [149]

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$47,360

Step-by-step explanation:

8 percent X 8years is equal to 64percent

74,000 X 64/100=47,360 dollars

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3 years ago

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3 years ago

antiderivative of Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the con

vlada-n [284]

Answer:

x^6 - (8/5)x^5 - 3x^3 + C.

Step-by-step explanation:

f(x) = 6x^5 - 8x^4 - 9x^2.

Using the general form antiderivative of Ax^m = Ax(m+1) / (m+1)+ C:

Antiderivative = 6 * x^(5+1) / 6 - 8 * x^(4+1) / 5 - 9 * x^(2+1) / 3 + C

= 6x^6/6 - 8x^5/5 - 9x^3/3 + C

= x^6 - (8/5)x^5 - 3x^3 + C.

Differentiating:

f'(x) = 6x^(6-1) - 8 x^(5-4) - 9x^(3-1) + 0

f'(x) = 6x^5 - 8x^4 - 9x^2.

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4 years ago

(02.03 MC) The temperature at a mountain base camp was −2 degrees Celsius on Thursday. Friday morning, the temperature was 1 deg

aev [14]

Answer:

The temperature at the base camp Friday evening is - 6 degrees Celsius.

Step-by-step explanation:

To get the temperature at a mountain base camp on Friday evening, we must translate statement into a mathematical form:

(i) The temperature at a moutain base camp was - 2 degress Celsius on Thursday:

$T_{o} = -2\,^{\circ}C$

(ii) Friday morning, the temperature was 1 degree Celsius lower than it was on Thursday:

$\Delta T_{1} = -1\,^{\circ}C$

(iii) Friday evening, the temperature was 3 degrees Celsius lower that it was that morning:

$\Delta T_{2} = -3\,^{\circ}C$

The temperature at the base camp Friday evening is:

$T = T_{o}+\Delta T_{1}+\Delta T_{2}$

$T = -2\,^{\circ}C-1\,^{\circ}C-3\,^{\circ}C$

$T = -6\,^{\circ}C$

The temperature at the base camp Friday evening is - 6 degrees Celsius.

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4 years ago