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3 years ago

What is 765903 rounded to the nearest hundred thousand

Mathematics

1 answer:

kramer3 years ago

7 0

765,903 in similar terms, the 7 in the hundred thousand place so 6 is greater is 5 so round up 800,000

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What are the comon factors of 70&20??

Musya8 [376]

70: 1,2,5,7,10,14,35,<span>70
20: 1,2,4,5,10,20</span>

3 0

4 years ago

A total of 259 tickets were sold to a benefit concert for a total of $5,312. Two types of tickets were sold: adult tickets were

jeyben [28]

Answer:

113

Step-by-step explanation:

Let the number of adult tickets sold =a

Let the number of student tickets sold =s

A total of 259 tickets were sold, therefore:

a+s=259

Adult tickets were sold for $24 each and student tickets were sold for $16 each.

Total Revenue = $5,312

Therefore:

24a+16s=5,312

We solve the two derived equations simultaneously.

From the first equation

a=259-s

Substitute a=259-s into 24a+16s=5,312

24(259-s)+16s=5,312

6216-24s+16s=5,312

-8s=5,312-6216

-8s=-904

Divide both sides by -8

s=113

Therefore, 113 student tickets were sold.

4 0

3 years ago

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

4 0

3 years ago

Whats 8/16 in decimal form

VikaD [51]

I believe the answer is
.5

7 0

3 years ago

DATA MANAGEMENT GRADE 12! HELP

Mashcka [7]

There are winnings of $50 ( 60% ), $100 ( 20% ) and $1,000 ( 2% ).
$50 * 0.6 = $30
$100 * 0.2 = $20
$1,000 * 0.02 = $20
$30 + $20 + $20 = $70
Answer: The expected payout per fan is $70.

4 0

3 years ago