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kherson [118]
3 years ago
5

How do you find the circumference of a circle

Mathematics
2 answers:
Verdich [7]3 years ago
6 0
Measure its diameter 
zloy xaker [14]3 years ago
4 0
To find the circumference of a circle you need to use the following formula...
c=pi(diameter)
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What is the solution for 2x + y =12 x = 9 - 2y
Andrew [12]

Answer:

x=5 and y=2

Step-by-step explanation:

I hope this helps

3 0
3 years ago
In the diagram, PQ¯¯¯¯¯¯¯¯ is tangent to the circle at point Q, and secant PS¯¯¯¯¯¯¯ intersects the circle at points R and S. Th
dimaraw [331]

The tangent secant theorem says

PR × PS = PQ²

4 × (4+5) = PQ²

36 = PQ²

PQ=6

Answer: 6

3 0
3 years ago
David goes into a candy store with $5.00. He buys 9 peppermints for $0.15 each and some sour candies. Each sour candy costs $0.2
Agata [3.3K]

Answer:

5 ≥ 9*.15 + x*.25

He can buy up to 14 candies

Step-by-step explanation:

Total money ≥number of peppermints * cost per peppermint + number of sour candies * cost per sour candy

We know he has 5 dollars.  He bought 5 peppermints at $.15 cents each and x sour candies at $.25 each

Substituting in

5 ≥ 9*.15 + x*.25

5≥1.35 + .25x

Subtract 1.35 on each side

5-1.35 ≥ 1.35-1.35+.25x

3.65≥.25x

Divide by .25 on each side

3.65/.25 ≥ .25x/.25

14.6 ≥ x

He can buy up to 14 candies.  You can't buy part of a candy

6 0
3 years ago
Let f(x)=cos(x)x^-2<br> F’(x)=
kondaur [170]

f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}

8 0
2 years ago
Simplify the difference quotient f(x)=x^2+9
Setler [38]

Answer:

sorry is its complicated

Step-by-step explanation:

Find the components of the definition.

f

(

x

+

h

)

=

x

2

+

2

h

x

+

h

2

−

9

f

(

x

)

=

x

2

−

9

Plug in the components.

f

(

x

+

h

)

−

f

(

x

)

h

=

x

2

+

2

h

x

+

h

2

−

9

−

(

x

2

−

9

)

h

8 0
3 years ago
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