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3 years ago

Find b for the following right angled triange where a=5 and c=13

1 answer:

4 0

You would use the Pythagorean there on which is a^2+b^2=c^2, from there you plug int what they gave you and solve for b, and b=12

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Please help it’s my final

katrin2010 [14]

Answer:

(p - 8)( p+4)

Step-by-step explanation:

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3 years ago

AB is a tangent. Find the length of the radius, r.

Lena [83]

Answer: 8

Step-by-step explanation:

Since AB is a tangent, angle CAB is a right angle. Thus, by the Pythagorean theorem, $r=\sqrt{17^{2}-15^{2}}=8$

4 0

2 years ago

2. The ratio of radii of two cylinders is 1:2 and heights are in the ratio 2:3. Find the ratio of their volumes.

Savatey [412]

Answer: $\frac{1}{6}$ or $1:6$

Step-by-step explanation:

The volume of a cylinder can be found with the following formula:

$V=\pi r^2h$

Where "r" is the radius and "h" is the height of the cylinder.

In this case, let be:

- $V_1$ the volume of one of this cylinders and $V_2$ the volume of the other one.

- $r_1$ the radius of the first one and $r_2$ the radius of the other cylinder.

- $h_1$ the height of one of them and $h_2$ the height of the other cylinder.

Then:

$V_1=\pi r_1^2h_1\\\\V_2=\pi r_2^2h_2$

Therefore, you know this:

$\frac{V_1}{V_2} =\frac{\pi r_1^2h_1}{\pi r_2^2h_2}$

Simplifying, you get:

$\frac{V_1}{V_2} =\frac{ r_1^2h_1}{ r_2^2h_2}$

Now, knowing the ratios given in the exercise, you can substitute them into the equation:

$\frac{V_1}{V_2} =\frac{1^2*2}{ 2^2*3}$

Evaluating, you get:

$\frac{V_1}{V_2} =\frac{2}{ 4*3}\\\\\frac{V_1}{V_2} =\frac{2}{12}\\\\\frac{V_1}{V_2} =\frac{1}{6}$

4 0

4 years ago

Solve the formula V=3/4 LWH for W

aniked [119]

W= 3/4 divided by LH

5 0

3 years ago

The birth weight of the child is ___ kilograms. The child gains an average of ___ per month.

Andru [333]

Answer:

3.5 kg, 0.5 kg

Step-by-step explanation:

The starting weight is represented by the y intercept, and the slope of the line is 0.5, so that's the average weight gain per month. Hope this helps!

4 0

3 years ago

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