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zhenek [66]
3 years ago
12

Ms. McClain conducted an experiment with a 6-sided number cube. The table shows the number of times each number landed:

Mathematics
2 answers:
netineya [11]3 years ago
8 0
A is the answer. ——————————————————-
nignag [31]3 years ago
3 0
Ii think the answer is A
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Help please
Vadim26 [7]
<span>✡ </span>Answer: 75; 100-25-5 ✡


- - To solve this you are going to subtract.
Because you are taking away apples, in this case eating them

- - So: 100-20-5

Answer: 75

✡Hope this helps!<span>✡</span>





7 0
3 years ago
Read 2 more answers
Find the surface area of this prism. geometry hw
Alexus [3.1K]

Answer:

395.2 cm²

Step-by-step explanation:

2x12.7x6.72=170.688

2x6.72x5.78=77.6832

2x5.78x12.7=146.812

170.688+77.6832+146.812=395.1832

4 0
2 years ago
Read 2 more answers
For the base b of a logarithmic function, b&gt;0 and b≠1<br><br><br> True<br><br> False
STatiana [176]
True cus i don’t remember but it’s true
4 0
3 years ago
What is the range of the function graphed below?
Akimi4 [234]

Answer:

C.

-  \infty  < y <   \infty

6 0
3 years ago
What is the function written in vertex form?
lys-0071 [83]

Answer:

The answer in the procedure

Step-by-step explanation:

The question does not present the graph, however it can be answered to help the student solve similar problems.

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If the coefficient a is positive then the parabola open up and the vertex is a minimum

If the coefficient a is negative then the parabola open down and the vertex is a maximum

case A) we have

f(x)=3(x+4)^{2}-6

The vertex is the point (-4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case B) we have

f(x)=3(x+4)^{2}-38

The vertex is the point (-4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

case C) we have

f(x)=3(x-4)^{2}-6

The vertex is the point (4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case D) we have

f(x)=3(x-4)^{2}-38

The vertex is the point (4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

4 0
3 years ago
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