Answer:
4.72 hours/day
Step-by-step explanation:
Mean time spent watching TV (μ) = 2.8 hours a day
Standard deviation (σ) = 1.5 hours a day
The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:
On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.
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Answer:
2/10
Step-by-step explanation:
0.20 = 20/100
20/100 = 2/10
Answer:
22/35
Step-by-step explanation:
-12/14=-6/7
-6/7*-11/15=66/105=22/35