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Assoli18 [71]
3 years ago
10

Jenna multiplied four numbers together and then divided by -2. The result was a positive value. Which of the following statement

s MUST be true? a) None of the factors were negative. b) All of the factors were negative. c) An odd number of factors were negative. d) An even number of factors were negative.
Mathematics
1 answer:
Yanka [14]3 years ago
4 0
)D is the answer, Plese don't descriminate if I'm wrong.
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Please help!! I will give brainilest. look at the picture!
xxMikexx [17]

Answer:

Rows 126

last row has 41

last row is not full because its an odd number

Step-by-step explanation:

4 0
3 years ago
What is the difference in length between a 1 1/4 inch button and a 3/8 inch button?
charle [14.2K]
1 1/4= 1*4+1 /4. Or 5/4

In order to subtract you must have same denominator. 5/4 -3/8

Multiply 5/4 times 2/2. =. 10/8. -3/8

The difference is 7/8
8 0
3 years ago
What is 213,548 to the nearest hundreds
Inga [223]

Answer:

Step-by-step explanation:

5 is in the hundreds place.

The answer should be 213500

8 0
3 years ago
Read 2 more answers
Sooooo bored ask me anything even if it´s not on the list
serg [7]

Answer:

What oets do you like? whats your height u noob

Step-by-step explanation:

6 0
3 years ago
Suppose that the time (in hours) required to repair a machine is an exponentially distributed random variable with mean 1/0.41/0
lbvjy [14]

Answer:

a) P(t>3)=0.30

b) P(t>10|t>9)=0.67

Step-by-step explanation:

We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.

The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.

The probabity that a repair time exceeds k hours can be written as:

P(t>k)=e^{-\lambda t }=e^{-0.4t}

(a) the probability that a repair time exceeds 3 hours?

P(t>3)=e^{-0.4*3}=e^{-1.2}= 0.30

(b) the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours?

The exponential distribution has a memoryless property, in which the probabilities of future events are not dependant of past events.

In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.

P(t>10|t>9)=P(t>1)

P(k>1)=e^{-0.4*1}=0.67

6 0
3 years ago
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