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3 years ago

Pls only answer if yk it ill give correct one BRAINLIEST!!

Mathematics

1 answer:

Dmitry [639]3 years ago

8 0

Answer:

X=10, x=4

Step-by-step explanation:

first, divide 14 by 2, and square it; giving you

x^2-14x+(7)^2=-40

Because 7^2 is 49, you have to add 49 to the other side; giving you

x^2-14x+(7)^2=9

Then factor the left side; giving you (x-7)^2=9

Take the square root of both sides, giving you

(x-7)^2= plus or minus 3

Then solve to get two solutions, 10 and 4

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What is (f - 5)(-2) + 11f

n200080 [17]

Answer:

-2f+10+11f

= 9f+10

Step-by-step explanation:

just expand it

7 0

2 years ago

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Pleas help me I have so much more left to do

Serjik [45]

Answer:

2 11/14 squared feet

Step-by-step explanation:

Area of a rectangle = length x width

Give length = 3 1/4 and

Width = 3/4

Therefore,

Area = 3 1/4 x 3/4

Change the mixed size fraction to an improperly fraction

We have A = 13/4 x 3/4

39/14

2 11/14 squared feet

6 0

3 years ago

A rectangle is 11 inches long and 8 inches wide. Find its area.

poizon [28]

Answer:

the answer is A:88 square inches

8 0

3 years ago

Read 2 more answers

In triangle ΔABC, ∠C is a right angle and CD is the height to

Zina [86]

Answer:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles $m\angle CDB=m\angle CDA=90$ °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

$m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha$

From ΔCBD,

$m\angle CBD$ is same as $m\angle B$ .

So, $m\angle CBD=90-\alpha$

$m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha$

Now, from ΔCAD,

$m\angle CAD$ is same as $m\angle A$

So, $m\angle CAD=\alpha$

$m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha$

Hence, the unknown angles of both the triangles are:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

5 0

2 years ago

This is a 3 part question, PLEASE HELP ILL GIVE BRAINLY

kaheart [24]

Answer:

Angle of A = 90 degree-62 degree = 28 degree.

Step-by-step explanation:

tan (62) = opposite / adjacent = 10 / a ---> a = 10/tan (62) = 10/ 1.88 = 5.319

cos (62) = a/c --->c = a/cos (62) = 5.319 / 0.47 = 5.3 / 0.47 = 11.3

or another way.

sin (62) = 10 /c ---> c = 10/ sin (62) = 10 / 0.88 = 11.3

So Angle of A = 28 degree.

a = 5. 3

c = 11.3.

please give me brainliest. I hope it help.

7 0

3 years ago